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Two Dimensional Motion. Vectors can be broken down into component x and y vectors. 120 N. q = 40 °. x = cos q (hypotenuse). y = sin q (hypotenuse). You can find a resultant vector by adding all of the x components and all of the y components. 4 N. 5 N. q 1 = 30 ° F = 5 N
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Vectors can be broken down into component x and y vectors 120 N q = 40° x = cosq(hypotenuse) y = sinq (hypotenuse)
You can find a resultant vector by adding all of the x components and all of the y components. 4 N 5 N
q1 = 30° F = 5 N q2 = 135° F = 2.5 N q3 = 330° F = 4.5 N 30° 45° 30° x = 5Ncos30° - 2.5Ncos45° + 4.5Ncos30° = 6.46 N y = 5Nsin30° + 2.5Nsin45° - 4.5Nsin30° = 2.02 N magnitude = 6.77 N direction = 17.4°
Projectiles Things moving in freefall with some velocity in the x direction The x and y motion are independent of each other and do not affect each other
Horizontally Launched Projectiles vx is constant vx = vx,i = vx,f
Vertical Motion of Horizontally Launched Projectiles vy,i = 0 g = -9.81 m/s2 Dy = ½(vi + vf)Dt vf = vi + aDt Dy = viDt + ½ aDt2 vf2 = vi2 + 2aDy Dy = ½vy,fDt vy,f = gDt Dy = ½gDt2 vy,f2 = 2gDy
I kick my calculator off the top of a 30 m building at 4 m/s. What formula would you use to answer the following questions? a) How fast will it be going vertically when it hits? b) How long will it take? c) How fast will it be going horizontally? d) How far will it go horizontally? vy,f2 = 2gDy vy,f = gDt vx,i = vx Dx = vxDt