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HOW DOES THE LATITUDE OF A LOCATION IMPACT THE INSOLATION THAT IT RECEIVES?. LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN. N. Equator. Center of Earth. S. LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN. North Pole Latitude = 90°N.
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HOW DOES THE LATITUDE OF A LOCATION IMPACT THE INSOLATION THAT IT RECEIVES?
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN N Equator Center of Earth S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN North Pole Latitude = 90°N Lat. = 90° Equator South Pole Latitude = 90°S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Z = 90° North Pole Latitude = 90°N Lat. = 90° Equator South Pole Latitude = 90°S Z = 90°
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Southampton, UK Latitude = 52°N Equator Punta Arenas, Chile Latitude = 52°S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Southampton, UK Latitude = 52°N Z = 52° Lat = 52° Equator Punta Arenas, Chile Latitude = 52°S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Southampton, UK Latitude = 52°N Z = 52° Lat = 52° Equator Punta Arenas, Chile Latitude = 52°S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Gainesville Latitude = 29.5°N Z = 29.5° Lat = 29.5° Equator Durban, SA. Latitude = 29.5°S
LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Quito, Ecuador Latitude = 0° Equator Lat = 0° Z = 0°
CAN WE QUANTIFY THIS EFFECT OF ZENITH ANGLE AT NOON AND LATITUDE? SUN N Imaginary solar collector of 1 m2 S
Ten parallel rays representing the solar constant (345Wm-2) SUN
North and South Poles (90°) SUN Z = 90°: 0/10 Rays intercepted = 0/10*345 = 0Wm-2
Southampton and Punta Arenas (52°) SUN Z = 52°: 6/10 Rays intercepted = 6/10*345 = 207 Wm-2
Gainesville and Durban (29.5°) SUN Z = 29.5°: 9/10 Rays intercepted = 9/10*345 = 310.5 Wm-2
Quito (0°) SUN Z = 0°: 10/10 Rays intercepted = 10/10*345 = 345 Wm-2
North and South Poles (90°) SUN Cos (90) = 0 0 * 345 = 0 Z = 90°: 0/10 Rays intercepted = 0/10*345 = 0Wm-2
Southampton and Punta Arenas (52°) SUN Cos (52) = 0.62 0.62 * 345 = 210 Z = 52°: 6/10 Rays intercepted = 6/10*345 = 207 Wm-2
Gainesville and Durban (29.5°) SUN Cos (29.5) = 0.87 0.87 * 345 = 310 Z = 29.5°: 9/10 Rays intercepted = 9/10*345 = 310.5 Wm-2
Quito (0°) SUN Cos (0) = 1.00 1.00 * 345 = 345 Z = 0°: 10/10 Rays intercepted = 10/10*345 = 345 Wm-2
ANSWER • Q = Cos(Z) * S Where Q = Quantity of insolation (Wm-2) Z = Zenith angle (noontime value controlled by latitude) S = Solar constant (345 Wm-2)