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RT || HI , RS || GI , S T || HG. Bisectors in Triangles. Lesson 5-2. Lesson 5-1 Quiz – Midsegments of Triangles. In GHI , R , S , and T are midpoints. 1. Name all the pairs of parallel segments. 2. If GH = 20 and HI = 18, find RT .
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RT || HI, RS || GI, ST || HG Bisectors in Triangles Lesson 5-2 Lesson 5-1 Quiz – Midsegments of Triangles In GHI, R, S, and T are midpoints. 1. Name all the pairs of parallel segments. 2. If GH = 20 and HI = 18, find RT. 3. If RH = 7 and RS = 5, find ST. 4. If m G = 60 and m I = 70, find m GTR. 5. If m H = 50 and m I = 66, find m ITS. 6. If m G = m H = m I and RT = 15, find the perimeter of GHI. 9 7 70 64 90 5-1
Bisectors in Triangles Lesson 5-2 When a point is the same distance from two or more objects, the point is said to be equidistantfrom the objects. Triangle congruence theorems can be used to prove theorems about equidistant points. 5-2
Bisectors in Triangles Lesson 5-2 5-2
Bisectors in Triangles Lesson 5-2 5-2
Bisectors in Triangles Lesson 5-2 The shortest segment from a point to a line is perpendicular to the line. This fact is used to define the distance from a point to a lineas the length of the perpendicular segment from the point to the line. 5-2
Bisectors in Triangles Lesson 5-2 5-2
Use the map of Washington, D.C. Describe the set of points that are equidistant from the Lincoln Memorial and the Capitol. Bisectors in Triangles Lesson 5-2 Additional Examples Real-World Connection The Converse of the Perpendicular Bisector Theorem states If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment. Quick Check 5-2
(continued) A point that is equidistant from the Lincoln Memorial and the Capitol must be on the perpendicular bisector of the segment whose endpoints are the Lincoln Memorial and the Capitol. Bisectors in Triangles Lesson 5-2 Additional Examples Therefore, all points on the perpendicular bisector of the segment whose endpoints are the Lincoln Memorial and the Capitol are equidistant from the Lincoln Memorial and the Capitol. Quick Check 5-2
Find x, FB, and FD in the diagram above. Bisectors in Triangles Lesson 5-2 Additional Examples Using the Angle Bisector Theorem FD = FB Angle Bisector Theorem 7x – 37 = 2x + 5Substitute. 7x = 2x + 42 Add 37 to each side. 5x = 42 Subtract 2x from each side. x = 8.4 Divide each side by 5. FB = 2(8.4) + 5 = 21.8 Substitute. FD = 7(8.4) – 37 = 21.8 Substitute. Quick Check 5-2
No; if CN = DN, CNBDNB by SAS and CB = DB by CPCTC, which is false. Bisectors in Triangles Lesson 5-2 Lesson Quiz Use this figure for Exercises 1–3. 1. Find BD. 2. Complete the statement: C is equidistant from ? . 3. Can you conclude that CN = DN? Explain. Use this figure for Exercises 4–6. 4. Find the value of x. 5. Find CG. 6. Find the perimeter of quadrilateral ABCG. 16 6 8 points A and B 48 5-2
Q P. Bisectors in Triangles Lesson 5-2 Check Skills You’ll Need (For help, go to Lesson 1-7.) 1. Draw a triangle, XYZ. Construct STV so that STVXYZ. 2. Draw acute P. Construct Q so that 3. Draw AB. Construct a line CD so that CDAB and CD bisects AB. 4. Draw acute angle E. Construct the bisector of E. TM bisects STU so that mSTM = 5x + 4 and mMTU = 6x – 2. 5. Find the value of x. 6. Find mSTU. Use a compass and a straightedge for the following. Check Skills You’ll Need 5-2
Bisectors in Triangles Lesson 5-2 Check Skills You’ll Need Solutions 1-4. Answers may vary. Samples given: 1. 2. 3. 4. 5. Since TM bisects STU, mSTM = mMTU. So, 5x + 4 = 6x – 2. Subtract 5x from both sides: 4 = x – 2; add 2 to both sides: x = 6. 6. From Exercise 5, x = 6. mSTU = mSTM + mMTU = 5x + 4 + 6x – 2 = 11x + 2 = 11(6) + 2 = 68. 5-2