1 / 7

EXAMPLE 5

EXAMPLE 5. Verify a trigonometric identity. Verify the identity cos 3 x = 4 cos 3 x – 3 cos x. cos 3 x. = cos (2 x + x ). Rewrite cos 3 x as cos (2 x + x ). = cos 2 x cos x – sin 2 x sin x. Use a sum formula.

twila
Download Presentation

EXAMPLE 5

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x =4 cos3 x – 3 cos x. cos 3x = cos (2x + x) Rewrite cos 3xas cos (2x + x). = cos 2xcos x – sin 2xsinx Use a sum formula. = (2 cos2x – 1) cosx –(2 sin x cosx) sinx Use double-angle formulas. = 2 cos3x – cosx – 2 sin2xcosx Multiply. = 2 cos3x – cos x – 2(1– cos2 x) cosx Use a Pythagorean identity. = 2 cos3x – cosx – 2 cosx + 2 cos3x Distributive property Combine like terms. = 4 cos3x – 3 cosx

  2. 3π 2 2 π 2 = , = EXAMPLE 6 Solve a trigonometric equation Solve sin 2x + 2 cosx = 0 for 0 ≤ x <2π. SOLUTION sin 2x + 2 cosx = 0 Write original equation. 2 sinx cosx + 2 cosx = 0 Use a double-angle formula. 2 cos x (sinx + 1) = 0 Factor. Set each factor equal to 0 and solve for x. 2 cosx sinx + 1 = 0 = 0 cos x = 0 sinx = –1 x x

  3. Graph the function y = sin 2x + 2 cosx on a graphing calculator. Then use the zero feature to find the x– values on the interval 0 ≤ x <2π for which y = 0. The two x-values are: 3π 2 π 1.57 and x x = = 4.71 2 EXAMPLE 6 Solve a trigonometric equation CHECK

  4. Find the general solution of 2 sin = 1. 2 sin = 1 5π 5π 6 3 2 sin = x x π 1 x x π x 2 2 3 2 2 2 6 General solution for = + 2nπ or 2 + 2nπ x = + 4nπ or + 4nπ EXAMPLE 7 Find a general solution Write original equation. Divide each side by 2. General solution for x

  5. for Examples 5, 6, and 7 GUIDED PRACTICE Verify the identity. 11. sin 3x = 3 sinx – 4 sin3x SOLUTION Sin 3x = sin (2x + x) = sin 2x cos x + cos 2x sin x = 2sin xcos xcos x + (1 –2 sin2x) sin x = 2 sin xcos2x + sin x –2 sin3x = 2 sin x(1 – sin2x) + sin x – 2sin3x = 2 sin x – sin3x + sin x – 2sin3x = 3 sin x – 4 sin3x

  6. for Examples 5, 6, and 7 GUIDED PRACTICE Verify the identity. 12. 1 + cos 10x = 2 cos2 5x SOLUTION 1 + cos 10x = 1 + 2 cos2(5x) – 1 = 2 cos2 5x

  7. ANSWER 4π 4π 5π 8π 2π 3 3 3 3 3 0, , , , , π π x 3 2 14. 2 cos+ 1 = 0 ANSWER + 4n π or + 4n π for Examples 5, 6, and 7 GUIDED PRACTICE Solve the equation. 13. tan 2x + tan x =0for0 ≤ x <2π.

More Related