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A car window is shaped like the trapezoid shown. Find the area of the window.

1 2. A = h ( b 1 + b 2 ) Area of a trapezoid. 1 2. A = ( 18 )( 20 + 36) Substitute 18 for h , 20 for b 1 , and 36 for b 2 . Areas of Trapezoids, Rhombuses, and Kites. LESSON 10-2. Additional Examples.

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A car window is shaped like the trapezoid shown. Find the area of the window.

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  1. 1 2 A = h(b1 + b2) Area of a trapezoid 1 2 A = (18)(20 + 36) Substitute 18 for h, 20 for b1, and 36 for b2. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples A car window is shaped like the trapezoid shown. Find the area of the window. A = 504 Simplify. The area of the car window is 504 in.2 Quick Check

  2. Draw an altitude from vertex B to DC that divides trapezoid ABCD into a rectangle and a right triangle. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples Find the area of trapezoid ABCD. Because opposite sides of rectangle ABXD are congruent, DX = 11 ft and XC = 16 ft – 11 ft = 5 ft.

  3. 1 2 A = h(b1 + b2) Use the trapezoid area formula. 1 2 A = (12)(11 + 16) Substitute 12 for h, 11 for b1, and 16 for b2. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples (continued) By the Pythagorean Theorem, BX2 + XC2 = BC2, so BX2 = 132 – 52 = 144. Taking the square root, BX = 12 ft. You may remember that 5, 12, 13 is a Pythagorean triple. A = 162 Simplify. The area of trapezoid ABCD is 162 ft2. Quick Check

  4. 1 2 A = d1d2Use the formula for the area of a kite. 1 2 A = (6)(5) Substitute 6 for d1 and 5 for d2. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples Find the area of kite XYZW. Find the lengths of the diagonals of kite XYZW. XZ = d1 = 3 + 3 = 6 and YW = d2 = 1 + 4 = 5 A = 15 Simplify. Quick Check The area of kite XYZW is 15 cm2.

  5. To find the area, you need to know the lengths of both diagonals. Draw diagonal SU, and label the intersection of the diagonals point X. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples Find the area of rhombus RSTU.

  6. SXT is a right triangle because the diagonals of a rhombus are perpendicular. 1 2 A = d1d2Area of a rhombus 1 2 A = (24)(10) Substitute 24 for d1 and 10 for d2. Areas of Trapezoids, Rhombuses, and Kites LESSON 10-2 Additional Examples (continued) The diagonals of a rhombus bisect each other, so TX = 12 ft. You can use the Pythagorean triple 5, 12, 13 or the Pythagorean Theorem to conclude that SX = 5 ft. SU = 10 ft because the diagonals of a rhombus bisect each other. A = 120 Simplify. Quick Check The area of rhombus RSTU is 120 ft2.

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