190 likes | 369 Views
-RC Circuits -Household Safety. AP Physics C Mrs. Coyle. RC Circuits. Resistors and Capacitors in the circuit. Two Situations for RC Circuits. Steady State. Variable Current. While the capacitor is charging or discharging. Occurs when the capacitor is fully charged
E N D
-RC Circuits-Household Safety AP Physics C Mrs. Coyle
RC Circuits • Resistors and Capacitors in the circuit.
Two Situations for RC Circuits Steady State Variable Current While the capacitor is charging or discharging • Occurs when the capacitor is fully charged • There is no current in the branch of the fully charged capacitor (it acts as an open circuit) • The current in the other braches is constant (steady state)
Charging a Capacitor in an RC Circuit • When the switch is closed, the capacitor starts to charge and the current is at maximum. • The current decreases as the capacitor continues to charge until it reaches its maximum charge (Q = CVc) • The potential difference increases until a maximum Vc. • Once the capacitor is fully charged, the current is zero. Vc
Steady State RC Circuit • When the capacitor is fully charged no current flows through the branch it is in. • The capacitor has its maximum voltage. • Sign convention for the capacitor voltage is the same as a battery: Vc is (+) when we traverse from the (–) to the (+) plate of the capacitor (low potential to high potential) -| |+
Example 1: What is the voltage and charge of the capacitor at steady state? • Ans: 10V, 20μC E=10V Vc C=2μF
Charging a Capacitor in an RC Circuit • The charge on the capacitor increases exponentially with time q=Q(1 – e-t/RC) t is the time constant = RC (unit: sec) • To find current as a function of time differentiate:q =C E (1 – e-t/RC)
Example 2 • Derive q =Q(1 – e-t/RC). • Hint: use Kirchhoff’ loop rule and substitute I=dq/dt
Time Constant and U • In a time t=RC then q=Q(1-e-1)=0.632Q • The time constant represents the time required for the charge to increase from zero to 63.2% of Q maximum. • The energy stored in the charged capacitor is U=½ Qe = ½ Ce2
Discharging a Capacitor in an RC Circuit q = Qe-t/RC • The charge decreases exponentially
Discharging a Capacitor in an RC Circuit • At t = = RC, q= Q e-1 = 0.368 Qmax • In one time constant, the capacitor loses 63.2% of its initial charge • Current:
Example 3 • When the switch is closed at steady state (when the capacitor is fully charged), what is the charge of the capacitor? • Hint: Apply Kirchhoff’s Rules • Ans: 8.0 x 10-6 C
Household Wiring • The utility company distributes electric power to individual homes by a pair of wires (one live and one neutral-ground) with a V of 120V • The potential of the neutral wire is taken to be zero • Each house is connected in parallel with these wires • The current and voltage are alternating
Short Circuit • A short circuit occurs when almost zero resistance exists between two points at different potentials • This results in a very large current • In a household circuit, a circuit breaker will open the circuit in the case of an accidental short circuit • This prevents any damage
Effects of Various Currents • 5 mA or less • can cause a sensation of shock • generally little or no damage • 10 mA • muscles contract • may be unable to let go of a live wire • 100 mA • if passing through the body for 1 second or less, can be fatal • paralyzes the respiratory muscles
Household Safety • Why should you not plug too many appliances in the same outlet? • What is the role of a circuit breaker? • Why should you not touch an electric appliance with wet hands? • What causes human injury current or voltage? • Why is grounding used?
More Effects • In some cases, currents of 1 A can produce serious burns • Sometimes these can be fatal burns • No contact with live wires is considered safe whenever the voltage is greater than 24 V
Ground-Fault Interrupters (GFI) • Special power outlets • Used in hazardous areas • Designed to protect people from electrical shock • Senses currents (of about 5 mA or greater) leaking to ground • Shuts off the current when above this level