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Physics 151: Lecture 12

Physics 151: Lecture 12. Today’s Topics: Review Springs Review Work - Energy Theorem. Problems we can do with that. Definition of Kinetic Energy :. The kinetic energy of an object of mass ( m ) moving at speed ( v ) is: K = 1/2 m v 2. Work Kinetic-Energy Theorem:. See text: 7-1.

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Physics 151: Lecture 12

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  1. Physics 151: Lecture 12 • Today’s Topics: • Review Springs • Review Work - Energy Theorem. • Problems we can do with that.

  2. Definition of Kinetic Energy : The kinetic energy of an object of mass (m) moving at speed (v) is: K = 1/2 m v2 Work Kinetic-Energy Theorem: See text: 7-1 Definition of Work: Work (W) of a constant force Facting through a displacement ris: W = F.r = Frcos  = Frr

  3. Question Planets go around the sun in elliptical orbits. The highly exaggerated diagram below shows a portion of such an orbit and the force on the planet at one position along that orbit. The planet is moving to the right. FT and FR are the components of the force parallel (tangential) and perpendicular (radial) to the orbit. The work they do is WT and WR at the position shown a. WT slows the planet down; WR speeds it up. b. WT slows the planet down; WR does no work on it. c. WT speeds the planet up; WR does no work on it. d. WT speeds the planet up; WR slows it down. e. WT does no work on it; WR speeds the planet up.

  4. Act 1 • When a crate of mass m is dragged a distance d along a surface with coefficient of kinetic friction , then dragged back along the same path to its original position, the work done by friction is : (a) 0 (b) -ukmgd (c) +ukmgd (d) -2ukmgd (e) +2ukmgd • When a ball rises vertically to a height h and returns to its original point of projection, the work done by the gravitational force is : (a) 0 (b) -mgh (c) +mgh (d) -2mgh (e) +2mgh Act 2

  5. Work Done Against Gravity • Consider lifting a box onto the tail gate of a truck. m h The work required for this task is, W = F.d = (mg)(h) (1) W = mgh

  6. Work Done Against Gravity • Now use a ramp to help you with the task. Is less work needed to get the box into the truck? (It’s “easier” to lift the box) m h

  7. N F mgsinq mg mgcosq Work Done Against Gravity m h q To push the box with constant speed, F = mgsinq The length of the ramp is h/sinq So the work done is, W = Fd = (mgsinq)(h/sinq) W = mgh Same as before !

  8. Lecture 13 -ACT 3Work of Springs • I have a spring with k = 20 N/m. Its compressed 30 cm by a 200 gram mass. How much work is done by the spring in this process ? A) 0.6 J B) 6 J C) 0.9 J D) –0.9 J

  9. Act 4 • Two clowns are launched from the same spring-loaded circus cannon with the spring compressed the same distance each time. Clown A has a 40-kg mass; clown B a 60-kg mass. The relation between their speeds at the instant of launch is: a) vA = 3/2 vB b) vA = (3/2 )1/2 vB c) vA = vB d) vB = (3/2 )1/2 vA e) vB = 3/2 vA

  10. Example Problem At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety device to stop the train so that it will not go plowing through the station if the engineer misjudges the stopping distance. While waiting, you wonder what would be the fastest train that the spring could stop by being fully compressed, 3.0 ft (~ 1m). To keep the passengers as safe as possible when the spring stops the train, you assume that the maximum stopping acceleration of the train, caused by the spring, is g/2. You make a guess that a train might have a mass of 0.5 million kilograms. For the purpose of getting your answer, you assume that all frictional forces are negligible. You find the maximum speed the train can have is: (A) < 5 mph (B) between 5mph and 10mph (C ) > 10 mph ( Note: 1 m/s ~ 2 mph )

  11. Lecture 13, ACT 5Work & Energy • Two blocks having mass m1 and m2 where m1 > m2. They are sliding on a frictionless floor and have the same kinetic energy when they encounter a long rough stretch (i.e. m > 0) which slows them down to a stop.Which one will go farther before stopping ? (a)m1(b)m2(c)they will go the same distance m1 m2

  12. Lecture 13, ACT 6Work & Energy • You like to drive home fast, slam on your brakes at the bottom of the driveway, and screech to a stop laying rubber all the way. It’s particularly fun when your mother is in the car with you. You practice this trick driving at 20 mph and with some groceries in your car with the same mass as your mama. You find that you only travel half way up the driveway. Thus when your mom joins you in the car, you try it driving twice as fast. How far will you go this time ? • The same distance. Not so exciting. •  2 times as far (only 7/10 of the way up the driveway) • twice as far, right to the door. Whoopee! • four times as far. Crashes into house. Sorry Ma.

  13. Another Example A 3.0-kg block is dragged over a rough horizontal surface by a constant force of 16 N acting at an angle of 37° above the horizontal as shown. The speed of the block increases from 4.0 m/s to 6.0 m/s in a displacement of 5.0 m. What work was done by the friction force during this displacement? a. –34 J b. –64 J c. –30 J d. –94 J e. +64 J

  14. Another Example 1. You have been hired to design a spring based toy pistol. The design criterion states that you have to be able to shoot an extremely aerodynamic bullet of mass 50 grams a distance of 20 meters. Unfortunately, there are not that many choices you can make, because the company insists on you using the left-over plastic gun-bodies from a previous, failed product. You do however have to design an appropriate spring. The gun body has a barrel of length10 cm on the outside and 8 cm on the inside. The entire plastic body has amass of 150g. You figure that the spring can fill the entire barrel, and can probably have a maximumcompression to about half of its original length. • What is the design of your spring ? (k=? ) k = 6.2 kN/m

  15. Recap of today’s lecture • Work/Energy Theorem • W = DK • Kinetic Energy • K = 1/2 mv2

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