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The Efficiency of Algorithms. Chapter 7. Chapter Contents. Motivation Measuring an Algorithm's Efficiency Big Oh Notation Formalities Picturing Efficiency The Efficiency of Implementations of the ADT List The Array-Based Implementation The Linked Implementation Comparing Implementations.
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The Efficiency of Algorithms Chapter 7
Chapter Contents • Motivation • Measuring an Algorithm's Efficiency • Big Oh Notation • Formalities • Picturing Efficiency • The Efficiency of Implementations of the ADT List • The Array-Based Implementation • The Linked Implementation • Comparing Implementations
Measuring Algorithm Efficiency • Algorithm has both time and space requirements called complexity to measure • Types of complexity • Space complexity • Time complexity • Analysis of algorithms • The measuring of either time/space complexity of an algorithm • Measure the time complexity since it is more important • Cannot compute actual time for an algorithm. • Give function of problem size that is directly proportional to time requirement: growth-rate function • Function measures how the time requirement grows as the problem size grows. • We usually measure worst-case time
Measuring Algorithm Efficiency Three algorithms for computing 1 + 2 + … n for an integer n > 0
Measuring Algorithm Efficiency The number of operations required by the algorithms
Measuring Algorithm Efficiency The number of operations required by the algorithms as a function of n
Big Oh Notation • Computer scientists use a notation to represent an algorithm’s complexity. • To say "Algorithm A has a worst-case time requirement proportional to n" • We say A is O(n) • Read "Big Oh of n" or “order of at most n” • For the other two algorithms • Algorithm B is O(n2) • Algorithm C is O(1)
Big Oh Notation Grows in magnitude from left to right… Tabulates magnitudes of typical growth-rate functions evaluated at increasing values of n When analyzing the time efficiency of an algorithm, consider larger problems. For small problems, the difference between the execution time is usually insignificant.
Formalities • Formal mathematical definition of Big OhAn algorithm's time requirement f(n) is of order at most g(n) • Big Oh provides an upper bound on a function’s growth rate. f(n) = O(g(n)) • That is, if a positive real number c and positive integer N exist such that f(n) ≤ c•g(n) for all n ≥ N c•g(n) is the upper bound on f(n) when n is sufficiently large.
Formalities An illustration of the definition of Big Oh
Example • Show that f(n) = 5*n + 3 = O(n) • g(n) = n, c = 6, and N = 3 • f(n) <= 6 g(n) • Why don’t we let g(n) = n^2 ? Let g(n) = n^2, c=8, N =1 • Although the conclusion is correct, it is not as tight as possible. • You want the upper bound to be as small as possible, and you want it to involve simple functions.
Formalities • The following identities hold for Big Oh notation: • O(k * f(n)) = O(f(n)) • O(f(n)) + O(g(n)) = O(f(n) + g(n)) • O(f(n)) * O(g(n)) = O(f(n) *g(n)) • By using these identities and ignoring smaller terms in a growth rate function, you can determine the order of complexity with little efforts. • O(4*n^2 + 50*n -10) = O(4*n^2) = O(n^2)
Picturing Efficiency Body of loop requires a constant amount of time O(1) an O(n) algorithm.
Picturing Efficiency An O(n2) algorithm.
Picturing Efficiency Another O(n2) algorithm.
Question? for i = 1 to n { for j = 1 to 5 sum = sum +1; } • Using Gig Oh notation, what is the order of the computation time?
Get a Feel for Growth-rate Functions The effect of doubling the problem size on an algorithm's time requirement.
Get a Feel for Growth-rate Functions • The time to process one million of problem size by algorithms of various orders at the rate of one million operations per second. • A programmer can use O(n2), O(n3) or O(2n) as long as the problem size is small
Efficiency of Implementations of ADT List • For array-based implementation • Add to end of list O(1) • Add to list at given position O(n) • For linked implementation • Add to end of list O(n)/O(1) • Add to list at given position O(n) • Retrieving an entry O(n)
Comparing Implementations The time efficiencies of the ADT list operations for two implementations, expressed in Big Oh notation
Choose Implementation for ADT • Consider the operations that your application requires • A particular operation frequently, its implementation has to be efficient. • Conversely, rarely use an operation, you can afford to use one that has an inefficient implementation.
Typical Growth-rate function • 1: implies a problem whose time requirement is constant and, therefore, independent of problem size n. • Log2n: time requirement for a logarithmic algorithm increase slowly as the problem size increases. If you square the problem size, you only double its time. • n: time requirement for a linear algorithm increases directly with the size of problem. If you squire the problem size, you also squire its time requirement. • n* Log2n: increases more rapidly than a linear algorithm. Such problem usually divide a problem into smaller problems that are each solved separately. • n^2: the time requirement for a quadratic algorithm increases rapidly with the size of the problem. Algorithms that use two nested loops are often quadratic. Such algorithm are practical only for small problem. • n^3: cubic algorithm increases more rapidly than quadratic algorithm. Algorithms that use three nested loops are often cubic. • 2^n: the time requirement for exponential algorithm usually increases too rapidly to be practical.
Exercises • Using Big Oh notation, indicate the time requirement of each of the following tasks in • the worst case. Describe any assumptions that you make. • a. After arriving at a party, you shake hands with each person there. • b. Each person in a room shakes hands with everyone else in the room. • c. You climb a flight of stairs. • d. You slide down the banister. • e. After entering an elevator, you press a button to choose a floor. • f. You ride the elevator from the ground floor up to the nth floor. • g. You read a book twice.
Exercises • Suppose that your implementation of a particular algorithm appears in Java as follows: • for (int pass = 1; pass <= n; pass++) • { • for (int index = 0; index < n; index++) • { • for (int count = 1; count < 10; count++) • { • . . . • } // end for • } // end for • } // end for • The algorithm involves an array of n items. The previous code shows the only repetition in the algorithm, but it does not show the computations that occur within the loops. • These computations, however, are independent of n. What is the order of the algorithm?
Exercises • What order is an algorithm that has as a growth-rate function of: • a. 8*n^3 -9*n • b. 7*log2 n + 20 • c. 9*log2 n + n • d. n*log2 n + n^2 • e. log2 (log2 n) + 3*log2 n + 4