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Magnetic Force on a Charged Particle

Magnetic Force on a Charged Particle. Source: Dr. Peggy Bertrand Oak Ridge HS. Chapter Assignments. Chapter 20 HW#1 Q2,3,9-11 and P1,7,8, HW#2 P11(c), 12-14,17(c), 26,29,30(c) , 48(c) and 49(c) Chapter 21 HW#3 Q2,4,6,8 and P1-5,9(c),10(c),14,15.

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Magnetic Force on a Charged Particle

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  1. Magnetic Force on a Charged Particle Source: Dr. Peggy Bertrand Oak Ridge HS

  2. Chapter Assignments • Chapter 20 • HW#1 Q2,3,9-11 and P1,7,8, • HW#2 P11(c), 12-14,17(c), 26,29,30(c) , 48(c) and 49(c) • Chapter 21 • HW#3 Q2,4,6,8 and P1-5,9(c),10(c),14,15

  3. 20-3 Force on Electric Current in Magnetic Field

  4. No force, vectors are parallel F = qvB = (3.0x10-6C)(3x105m/s)(200x10-3 T) F = 1.8x10-1 N down

  5. F = qVB sin q direction: up

  6. Motion of Charged Particles in a Magnetic Field

  7. +q is forced down toward the bottom of the page

  8. F = qvB • B = F/qv = 2000N • C(1.6x10 -19C)(3x105 m/s) • B = _____T

  9. F = qVB = (1.60x10-19 C) (300,000 m/s) (2000x10-3 T) Direction: out of the page

  10. F = Eq = 2000 N/c (1.60 x 10-19 c) = Direction: out of page (use left hand for electron)

  11. F = qVB = 1.60 x 10 -19 c (300,000 m/s)(2 T) = Direction: down

  12. Magnetic Force on Current Carrying Wires

  13. B = F/qV = 400V/20,000 m/s = A volt is work done per unit charge (J/q) Direction: into the page

  14. F = I L B sin Q F = (30A)(100m)(0.4T)(sin90) F = _____________N

  15. F = I L B  B = F / I L = (40N/m) / 15A = Current moving to the right

  16. Sources of Magnetic Fields

  17. Announcement Mechanics Review this week Wednesday from 0830 - 0900

  18. More on Sources of B Fields

  19. r2 r 1 Opposite Directions could be zero I1 = 10.0 A I2 = 13.0 A 7.0 m

  20. I B A B - out A - in

  21. Magnetic Flux

  22. 0 • Max: F = BAcos q = 4.2x10-3T(6m2)cosq = ___ Weber • c) F = BAcos q = 4.2x10-3T(6m2)cos30 = ___ Wb

  23. F = B p r2 cos 40 r = sr [F / B p cos 40] r = sr [.250Wb / (0.050T)(3.14)(cos40) = ______m

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