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Unit 4 Acids,Bases and Salts. Quiz 1 topics. Definitions Theories Properties Hebden IV.1-IV.4 (pages 109-118). Properties of an Acid. An acid is any substance that turns blue litmas paper red Reacts with metals to produce hydrogen Conduct electricity Sour taste
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Quiz 1 topics • Definitions • Theories • Properties • Hebden IV.1-IV.4 (pages 109-118)
Properties of an Acid • An acid is any substance that turns blue litmas paper red • Reacts with metals to produce hydrogen • Conduct electricity • Sour taste • React Exothermically with Bases • Functional Definition of an Acid: An acid is any substance that turns blue litmas paper red (Grade 10 definition)
Properties of A Base • Any substance that turns red litmus paper Blue • Are electrolytes • Are Slippery (Corrosive to skin) • Taste Bitter • React Exothermically with Acids • Functional Definition: Any substance that turns red litmus paper Blue (Grade 10)
Problems with the functional Definitions of Acids &Bases • The functional definitions of acids and bases allowed chemists to classify compounds, however, they are not very useful because they provide no theory as to how they work.
Common Acids & bases • Acids • Sulphuric acid • Hydrochloric Acid (Muriatic) • Nitric Acid • Acetic Acid • Bases • Sodium Hydroxide • Potassium Hydroxide (potash) • Ammonia (Ammonium Hydroxide)
Arrhenius Theory/Definition • An Acid is any substance which releases H+ in water • Base is any substance which releases OH- in water • A Salt is the neutralization product which results when an acid and a base react. Acid + Base => Water + Salt (A Salt is any ionic compound which is neither an acid nor a base)
Problems with the Arrhenius theory • Arrhenius’s theory and definitions arte better than the functional definitions because they explain how acids and bases interact. • The main problem with the Arrhenius’s theory is that there are examples of compounds that follow the functional definitions of a base but not the Arrhenius definition (Example NH3)
Classification of Acids • Monoprotic Acid, is an acid which can supply only one proton. • Diprotic Acid, is an acid that can supply two protons • Triprotic Acid, is an acid that can supply three protons • Polyprotic acid, is a general term for an acid that can supply mote than 1 proton.
Bronsted-Lowery Theory(Grade 12 Definitions) • An Acid is any substance which Donates a Proton to another substance • A Base is any substance which Accepts a Proton from another Substance • Examples
Amphiprotic compounds • Amphiprotic compounds are compounds that can act either as an acid or a base. I.e. as a proton acceptor or a proton donor. Most amphiprotic compounds contain hydrogen ions that can be donated and have a negative charge (I.e are anions) (exception is water) • Examples
Conjugate Acid/base pairs • A conjugate acid-base pair (conjugate pair) is a pair of chemical species that differ by only one proton. • Conjugate Acid: is the member of the pair that has the extra proton (H+ ion) • Conjugate base: is the member of the pair that lacks the extra proton.
Quiz 2 • Conjugate acid/base pairs • Strengths of acids and bases • Ka, Kb, and Kw’s • Hebden IV.5- IV.10 (120-133)
Strength of Acids and Bases • Acid strength is a measure of how willing a compound is to donate a proton (H+ ion) • The strength of a base is a measure of how willing a compound is to accept a proton • ** In water, the strongest acid is the H3O+ ion. In water the strongest base is the OH- ion. This is called the Leveling effect • A Strong Acid is a compound that donates a proton and dissociates 100% in water • A Strong base is a compound is 100% ionized in water and will accept a proton
Dissociation Expression for H2O • Keq =[products]/[reactants]= [H3O+][OH-]=1.00x10-14 =Kw (at 25C) • [H3O+]=[OH-]=1.00x10-7 • We say H2O is neutral because the [H3O+]=[OH-] • We say a solution is acidic if [H3O+]>[OH-] • We say a solution is basic if [H3O+]<[OH-] • Note: KW does depend on temperature as can be seen by the dissociation eqs.
Ka & Kb for determining the relative strengths of Acids and Bases • Using the fact that water is neutral I.e., [H3O+]=[OH-] and amphiprotic, we can establish the relative strengths of acids and bases by comparing them to H2O • In order to be able to use Ka as a measure of acid strength, the same base must be used in both cases. Water is chosen because it neutral
Quiz 3 • pH, pOH, [H3O+], [OH-] • For strong acids and bases
Ka Calculations • Since Strong Acids/Bases dissociate 100% so pH, pOH, etc calculations are straight forward. • This is not the case for Weak Acids or bases. • In order to calculate H3O+ or OH- concentrations Ka/Kb data must be used
Types of Ka problems • Given: [HA], Ka Calculate pH or [H3O+] • Given: [HA], pH or [H3O+] Calculate Ka • Given: Ka, pH or [H3O+] Calculate [HA] • HA is a weak acid
Kb Problems • Kb problems are very similar to Ka problems except you will be writing Kb expressions and you will have to calculate Kb from Ka • Given: [A-], Kb Calculate pOH or [OH-] • Given: [A-], pOH or [OH-] Calculate KB • Given: Kb, pOH or [OH-] Calculate [A-] • A- is a weak base
Making Acids from Anhydrides • You can prepare an acid from an anhydride by hydrating it (i.e adding water) • Ex1: Covalently bonded molecules containg oxygen • Ex adding water to an Acidic anhydride
Hydrolysis & Anhydrides • An anhydride is a chemical compound formed by removing water. Salts formed in acid/base reactions are anhydrides because: • Hydrolysis, is when an Anhydride reacts with water Anhydride rx. Hydrolysis rx.
Anhydrides • Anhydrides can be prepared by driving off water, or, any acid/base rx will produce an anhydride salt. • Examples • ** not all anhydride salts can under go hydrolysis • The conjugates of strong acids & strong bases can not under go hydrolysis and are called spectator ions in solution
Spectator Ions(will not under go Hydrolysis) • Cations: all group 1 and group 2 metals • Anions: 5 anions found at top of Acid Strength table ( ClO4-, I-, Br-, Cl-, NO3-)
Titrations Quiz • Titration Curves • How to choose and indicator • How an indicator works • Primary standard vs. Secondary standard • Titration problems
Titration Problems • Titration: is an experimental process of determining when a balanced reaction has reached its correct stoichiometric ratio • Grade 11- finding the concentration of an unknown acid/base (N,C,V problem) • Grade 12 problems • Percent purity problem • 34.786 g of NaHSO4(impure) is diluted to 250.0 ml of solution, 25.0 ml of this was titrated with 26.77 ml of NaOH with a Molality of 0.9974 what is the % purity of the NaHSO4
Titration Problems • Determining molar mass • 3.2357 g of a monoprotic acid is diluted to 250.00 ml 25.00 is titrated with 16.94 mL of a 0.1208 M solution NaOH what is the molar mass of the compound? • Partial Neutralizations involving multi-protic acids • An equivalence point is reached by reacting 25.00 mL of a 0.11255 M NaOH solution with 38.74 ml of a 0.02700 M H4P2O7 How many protons have been removed? What is the balanced reaction?
Primary vs. Secondary Standards • Primary standard: a substance which can be obtained in a pure and stable form (which does not absorb water or CO2 from the air) and from which a solution of exactly known concentration can be prepared • Secondary standard: are derived from primary standards by preforming titrations to determine the exact concentration (example NaOH solution)
How an Indicator works • An indicator is a week acid in which its conjugate base is a different color • NOTE: The pH of the end point color of an Indicator is = Pka or the Indicator(week acid)
Buffers • Definition: A buffer is a solution containing appreciable amounts of a weak acid and its conjugate pair • Example: HF +H2O <=> F- + H3O+ ( 1 M) (1 M) To prepare a Buffer you make a solution containing equal concentration of a weak acid and its conjugate • The pH of a buffered solution will equal the Pka of the weak acid. This is because [HA] = [A-] so that in the Ka expression they cancel out in this manner you can prepare buffer systems with specific pH’s.
Buffers in Biological systems • Blood/Oxygen equilibrium • CO2/HCO3- Buffer System CO2 + 2H2O <=> HCO3- +H3O+