1 / 11

Physics 2053C – Fall 2001

Physics 2053C – Fall 2001. Motion, Energy, Waves & Heat. Course Organization. Lecture: Monday, Wednesday and Friday 10:10 to 11:00 Quizzes during Wednesday AM Tutorials: Monday: 12:00 – 3:00 Tuesday: 9:00 – 12:00 Labs: Tuesday or Thursday afternoons evenings.

valin
Download Presentation

Physics 2053C – Fall 2001

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Physics 2053C – Fall 2001 Motion, Energy, Waves & Heat Dr. Larry Dennis, FSU Department of Physics

  2. Course Organization • Lecture: • Monday, Wednesday and Friday 10:10 to 11:00 • Quizzes during Wednesday AM • Tutorials: • Monday: 12:00 – 3:00 • Tuesday: 9:00 – 12:00 • Labs: • Tuesday or Thursday afternoons evenings

  3. Why do you need to understand Physics? • Foundation on which all modern science is built – and it is becoming more and more important. • Useful for almost all careers. • Teaches a particular way of addressing problems and observing the environment. • Helps you understand what is possible.

  4. Units • Physical measurements require: • units • a frame of reference 500 500 meters 500 meters south of the dock

  5. Conversion of Units 1 in = 2.54 cm = 0.0254 m = 0.0833 ft = 1.58 x 10-5 mi 70 mph = 70 mi/hr = 70 mi/hr x 5280 ft/mi x 1 hr/3600 sec = 70 x 5280 / 3600 x mi/hr x ft/mi x hr/s = 103 ft/s = 103 ft/s x 12 in/ft x 0.0254 m/in = 31.4 m/s (also 113 km/hr)

  6. Kinematics • Motion in 1-D. • Free fall. • Along a road. • Displacement. • Velocity. • Acceleration.

  7. Average Velocity = distance traveled elapsed time = 6 km – 3 km + 5 km 2 hr + 1 hr + 2 hr = 8 km/5 hr = 1.6 km/hr 6 km in 2 hours 3 km in 1 hour 5 km in 2 hours Average Velocity

  8. Average Acceleration Average Acceleration = change in velocity elapsed time aave = ( v2 – v1 ) = v ( t2 – t1 ) t ains = limit v t -> 0t

  9. x (m) t (s) Motion at Constant Acceleration x = x0 + v0 t + ½ a t2 v2 = v02 + 2 a (x – x0) v = v0 + a t

  10. Sample Problem • How fast is he moving at the end of 5 seconds? • How far has he gone in the 5 seconds? • What is his average speed for the 5 seconds? • How far does he go between 5 and 10 seconds? • What is his average velocity over 10 seconds? A police car starts from rest and accelerates at a constant rate of 3 m/s2 for 5 seconds and then continues moving with constant speed.

  11. Next Time • Read Chapter 1 & 2. • Start CAPA – you must get a CAPA id to be able to do your homework. • No tutorial on Monday. • See me with any questions or comments. See you Wednesday.

More Related