1 / 5

Expected Values US 5258 3 Credits Internal Finding the Variance

Large spread. Expected Values US 5258 3 Credits Internal Finding the Variance The questions in the assessment will also ask you to find the variance, which is a measure of spread. Small spread. Multiply the values in the x column by the values in the p column.

valora
Download Presentation

Expected Values US 5258 3 Credits Internal Finding the Variance

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Large spread Expected Values US 5258 3 Credits Internal Finding the Variance The questions in the assessment will also ask you to find the variance, which is a measure of spread Small spread

  2. Multiply the values in the x column by the values in the p column Multiply the values in the X 2 column by the value in the p column Add this column up Finally, add this column up Square the values in the x column To find the variance, use the total of the last column, X 2 * p, and subtract the square of the total of the 3rd column, 2 The variance, VAR(X) = Sum(X 2 * p) - 2

  3. (These are the same examples from the Expected Values PowerPoint) Example 1: 10 coins are placed in a bag, three 10 cents, 5 20 cents and two 50 cents. What is the variance of the coins values? The variance, VAR(X) = Sum(X 2 * p) - 2 = 730 – 232 = 201

  4. Example 2: Find the variance from the following table VAR(X) = Sum(X 2 * p) - 2 = 290 – 162 = 34

  5. Example 3: Find the variance from the following table Var(X) = Sum(X 2 * p) - 2 = 7.125 – 2.3752 = 1.48

More Related