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Conservation of Energy. Forms of energy. You add energy to a system by doing work on it. If you do work on an object, it may: Accelerate…adding kinetic energy Be lifted…adding gravitational potential energy Bend…adding elastic potential energy. Work = force x distance.
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Forms of energy • You add energy to a system by doing work on it. • If you do work on an object, it may: • Accelerate…adding kinetic energy • Be lifted…adding gravitational potential energy • Bend…adding elastic potential energy • Work = force x distance • The work you do is the energy it gains!
How much work is done? A car exerts a force of 2500 N against the road as it accelerates over 63 m. 2500 N 63 m
How much work is done? A 1200 kg car accelerates at 4.1 m/s2 over a distance of 75 m. a=4.1m/s2 1200kg 75m
How much work is done? A forklift raises a 250 kg crate 3.2 m above the ground. 3.2m 250kg
How much work is done? A 75 kg sprinter reaches 11 m/s at 3.1 s in a race. 75kg vf=11 m/s at 3.1 s
How much work is done? • A car exerts a force of 2500 N against the road as it accelerates over 60 m. • A 1200 kg car accelerates at 4.1 m/s2 over a distance of 75 m. • A 75 kg sprinter reaches 11 m/s at 31 m in a race. • A forklift raises a 250 kg crate 3.2 m above the ground.
Shall we return to the braking distance problem? When a car is braking, the tires do work against the road in the direction opposite to its motion. The work done decreases kinetic energy of the car. When KE=0 J, the car is at rest
Shall we return to the braking distance problem? • The road can offer a car exactly 1/3 of its weight in friction with the tires at full braking. Suppose the car has a mass of 1100 kg (weight = 10800 N) • How much friction does the road provide? b) If the car is moving at 25 m/s, how much kinetic energy does it have? c) How far does it brake before KE0.0 J?
Shall we return to the braking distance problem? • The road can offer a car exactly 1/3 of its weight in friction with the tires at full braking. Suppose the car has a mass of 1100 kg (weight = 10800 N) • How much friction does the road provide? b) If the car is moving at 50 m/s, how much kinetic energy does it have? c) How far does it brake before KE0.0 J?
Triple axel • http://www.youtube.com/watch?v=XzFGzsn6Skg • Slam dunk • http://www.youtube.com/watch?v=fVmZnvdzAC0
55kg kid, 2.0 m fall.Make a table of GPE, KE, and velocity • Ht. GPE KE v • 2.0m • 1.5m • 1.0m • .5m • 0m
How much work is done? • An 84 kg science teacher runs up Pikes Peak. The race includes a vertical climb of 2410 m.
How much work is done? An 84 kg science teacher runs up Pikes Peak. The race includes a vertical climb of 2410 m.
A student runs… …or walks if he is a SLACKER! • …up three flights of stairs. How much work is done?
A student runs… …or walks if he is a SLACKER! • …up three flights of stairs. How much work is done? • I dunno. What is YOUR mass, and how high is the lunchroom?
Find three ways to measure the height of the lunchroom (above the first floor)
Power Lab • Measure the change in height from the first to fourth floors. • Run (or walk) up the stairs, measure and record the time required • Calculate: Work done and power for this trip
Momentum=mass x velocity p=m x v • The units of momentum are kg m/s
In a collision: Momentum is conserved! Momentumbefore=Momentumafter p initial=p final
Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
Elastic Collisions Before: After:
What is the momentum of….? • A pitched baseball? • A sprinter? • A car on Louisiana Ave.? • A car on I-25? • A semi on I-25? • An aircraft carrier at the dock?
What is the momentum of….? • A pitched baseball? (.15kg, 45m/s) • A sprinter? (60 kg, 10 m/s) • A car on Louisiana Ave.? (1000 kg, 15 m/s) • A car on I-25? (1000 kg, 35 m/s) • A semi on I-25? (15000 kg, 35 m/s) • An aircraft carrier at the dock? (200000000 kg, 0 m/s)
What is the kinetic energy of….? • A pitched baseball? (.15kg, 45m/s) • A sprinter? (60 kg, 10 m/s) • A car on Louisiana Ave.? (1000 kg, 15 m/s) • A car on I-25? (1000 kg, 35 m/s) • A semi on I-25? (15000 kg, 35 m/s) • An aircraft carrier at the dock? (200000000 kg, 0 m/s)
A change in momentum: …if momentum is mass x velocity— …and the mass of an object can’t change, then it’s a change in velocity
A change in momentum: …if momentum is mass x velocity— …and the mass of an object can’t change, then it’s a change in velocity =acceleration x time =Force/mass x time
Did you notice? While work is force x distance, a change in momentum is force x time! m x Dv=m x (a x t)=m x (F/m x t)=F x t
Did you notice? While work is force x distance, a change in momentum is force x time! m x Dv=m x (a x t)=m x (F/m x t)=F x t • This is called an impulse: • Dp=mDv=Ft
Try it. • If a 10. kg object at rest is pushed with a force of 20. N (total) for 10. s…
Try it. • If a 10. kg object at rest is pushed with a force of 20. N (total) for 10. s… • The impulse is F x t
Try it. • If a 10. kg object at rest is pushed with a force of 20. N (total) for 10. s… • The impulse is F x t = 20. N x 10. s = 200 Ns = 200 kg m/s
Try it. • If a 10. kg object at rest is pushed with a force of 20. N (total) for 10. s… • The impulse is F x t = 20. N x 10. s = 200 Ns = 200 kg m/s • Did you notice? • The acceleration is 2.0 m/s2 • The final velocity is 20 m/s • The final momentum is 200 kg m/s
Consider a 15 kg object, accelerated by a 30 N force. • If the force is applied for 100 m… • ?a • ?t • ?vf • ?p • ?KE • ?W • If the force is applied for 10 s… • ?a • ?d • ?vf • ?p • ?KE • ?W
Crash test videos • http://www.youtube.com/watch?v=sh1-ti8cCiw • Introduction • http://www.youtube.com/watch?v=FnH_gvhI9OI • Basic crash • http://www.youtube.com/watch?v=d7iYZPp2zYY • Seat belt and airbag • http://www.youtube.com/watch?v=fPF4fBGNK0U • Old vsnew cars