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Practice with Molar Mass Problems

Practice with Molar Mass Problems. x 1 mol H 2. 2.02 g H 2. : Question #1. How many moles of H 2 are in 100 g of H 2 ?. # mol H 2. = 100 g H 2. = 49.5 mol H 2. x 1 mol CuSO 4. 159.61 g CuSO 4. Question #2.

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Practice with Molar Mass Problems

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  1. Practice with Molar Mass Problems

  2. x 1 mol H2 2.02 g H2 :Question #1 How many moles of H2 are in 100 g of H2? # mol H2 = 100 g H2 = 49.5 mol H2

  3. x 1 mol CuSO4 159.61 g CuSO4 Question #2 300 g of CuSO4 is needed in an experiment. How many moles does this represent? # mol CuSO4 = 300 g CuSO4 = 1.88 mol CuSO4

  4. x 143.32 g AgCl 1 mol AgCl Question #3 A chemical reaction requires 23.78 moles of silver chloride. How many grams is this? # g AgCl = 23.78 mol AgCl = 3408 g AgCl

  5. x 6.02x1023 molecules 1 mol H2O x 1 mol H2O 18.02 g H2O Question #4 How many molecules are in 73 grams H2O? # H2O molecules = 73 g H2O = 2.4 x 1024 molecules H2O

  6. x 1 mol Ca3(PO4)2 310.18 g Ca3(PO4)2 Question #5 255 g of calcium phosphate are produced in a chemical reaction. How many moles of calcium phosphate does this represent? # mol Ca3(PO4)2 = 255 g Ca3(PO4)2 = 0.822 mol Ca3(PO4)2

  7. 2 mol H2O 18.01 g H2O 265 g H2O x x = 1 mol O2 1 mol H2O Question #6 According to the equation 2H2 + O2 2H2O, how many grams of H2O would be produced if 7.35 mol of O2 is used up? (hint: you will need two conversion factors – 1 from the balanced equation and 1 from a molar mass) # g H2O= 7.35 mol O2

  8. And you thought Chemistry was bad with factor-label problems!!??

  9. Complete the following chart (#7 - #13):

  10. Formula Molar mass (g/mol) Mass (g) Moles (mol) Complete the following chart (answers): FeSO4 151.9 500 3.29 (NH4)2CO3 96.1 192.2 2 SnO2 150.7 50 0.332 Sb2O5 323.6 80.9 0.25 NaClO4 122.4 100 0.817 Mg(IO3)2 374.1 1196.8 3.2 CoCl2.H2O 147.8 332 2.246

  11. Assignment 14. AgCl = 143.35 g/mol #g = 2 mol x 143.35 g/mol =286.7 g (2) 15. H2 = 2.016 g/mol #mol = 100 g x mol/2.016 g =49.6 mol (2) 16. CuSO4 = 159.62 g/mol #mol= 300 g x mol/159.62 g=1.879 mol (2) 17. KClO = 90.55 g/mol #mol = 250 g x mol/90.55 g =2.76 mol (2)

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