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Chm08 Oxidation-Reduction Reactions and Activity Series

Chm08 Oxidation-Reduction Reactions and Activity Series. Activity of Halogens F 2 Cl 2 Br 2 I 2. Will the 1 st element replace the 2 nd ? Mg  Ag K  Li Pb  Cu Na  Ca Br  F Cl  I. Increasing activity. Will this reaction occur? (Use Activity Series). Zn + Na 2 O →

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Chm08 Oxidation-Reduction Reactions and Activity Series

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  1. Chm08 Oxidation-Reduction Reactions and Activity Series

  2. Activity of Halogens F2 Cl2 Br2 I2 Will the 1st element replace the 2nd?Mg  AgK  LiPb  CuNa  CaBr  FCl  I Increasing activity

  3. Will this reaction occur? (Use Activity Series) • Zn + Na2O → • Li + AgNO3 → • Fe + CuSO4 → • Cl2 + KF → • Al + CaSO3 → • F2 + BaI2 →

  4. Rules for Assigning Oxidation Numbers • The oxidation # of an atom in the elemental state is zero.Ex: Cl2 and Al both are 0 • The oxidation # of a monatomic ion is equal to its charge.Ex: In the compound NaCl, the sodium has an ox. no. of 1+ and the chlorine is 1-. • The algebraic sum of the oxidation # in the formula of a compound is zero.Ex: the oxidation numbers in the NaCl above add up to 0 • The oxidation # of hydrogen in a compound is 1+, except when hydrogen forms compounds called hydrides with active metals, and then it is 1-.Ex: H is 1+ in H2O, but 1- in NaH (sodium hydride). • The oxidation # of oxygen in a compound is 2-, except in peroxides when it is 1-, and when combined with fluorine. Then it is 2+.Ex: In H2O the oxygen is 2-, in H2O2 it is 1-. • The algebraic sum of the oxidation # in the formula for a polyatomic ion is equal to the charge on that ion.Ex: in the sulfate ion, SO42-, the oxidation numbers of the sulfur and the oxygens add up to 2-. The oxygens are 2- each, and the sulfur is 6+.

  5. Assigning Oxidation Nos. MgO 4) FeI3 5) Cu • K2(CrO4) 2) KMnO4

  6. 1) Practice: (LEO goes GER) • Given the unbalanced equation below: Cr2O3(s)  +  Al(s) ---->  Cr(s)  +  Al2O3(s) • Identify the oxidation state of each element b. Which element is oxidized (lose e-)? c. Which element is reduced (gain e-)?

  7. 2) Practice: (LEO goes GER) • Given the unbalanced equation below: Fe2O3 + CO → CO2 + Fe • Identify the oxidation state of each element b. Which element is oxidized (lose e-)? c. Which element is reduced (gain e-)?

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