Acid – Base Titration
Acid – Base Titration. Prelab question. M A x #H x V A = M B x #OH x V B M A = 6 M, #H = 2, V A = ? M B = 0.5 M, #OH = 1, V B = 0.5 L (6 M)(2)(V A ) = (0.5 M)(1)(0.5 L) V A = (0.5 M)(1)(0.5 L) / (6 M)(2) V A = 0.25 mol / 12 M = 0.0208 L = 2 0.8 mL.
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