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TE 01 disk-loaded guide (coaxial) load. No electric field terminating on a conductor. No axial currents. No currents at wave-guide disk interface Attenuator and filter. Broadband matching to disk loaded guide. match. =Z.
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TE01 disk-loaded guide (coaxial) load • No electric field terminating on a conductor. • No axial currents. • No currents at wave-guide disk interface • Attenuator and filter. • Broadband matching to disk loaded guide.
match =Z
Obtain disk radius ra and mechanical period pz of the matching cells. • With a given ra vary pz to obtain a 90 degree phase advance at 11424 MHz. Note Z. • Obtain functions ra(Z) and pz(Z).( Polynomial ) • Insert the values of Z that are required to yield a Butterworth function for Gin and obtain ra and pz for the matching cells. • Cascade the cells.
vgg p/2 cells vgg1.smx 1.125” smatr 11424 MHz 0.375” Inner conductor p/2 Outer conductor ra and pz as a function of Inner conductor group velocity
ra=1.8617 pz=2.01cm vg=9.09 [%C] Q=567 90degrees at 11424 MHz ra(Z), pz(Z) Din=0.75 inch Dout=2.25 inch Att=0.407 dB/cell sinctp P=100 MW For 20 dB round trip att.: Nac=20, Lac=34 cm Emax=39 MV/m Hmax=0.125 MA/m
Sincel.mac ra.=1.9, pz=2.04, rin=.95 rout=2.857 cm Vg=7.22 Single cell Apc=0.513 dB/cell 90 degrees Pin=100 MW For 20 dB round trip att.: Nac=17 Lac=34 cm 11424 MHz Hmax=0.15 MA/m Emax=49 MV/m
P=100 Mw Pdmax=5.5 % Po16ac0_1 L=19 cm s=1122000 Vmax=9.15 [%C] m=11 Att=1.55 dB
P=100 MW Dcc1=1.300 Pdmax=5.5% Po16ac0_2 L=19 cm input output Att=1.66 dB
nac4_1 po16ac4 Dcc1=1.1300 output Att=3.189dB, 0.4 dB/cell input
Reflection and attenuation output nac5 input Att=3.79 dB 0.6dB/cell
P=100 MW Emax=30 MV/m Hmax=.1 MA/m nac6 Att=4.25 dB, 0.46 dB/cell For 20 dB round trip attenuation, L=9.5+ 36= 45.5 cm
mawgco P=100 MW Att=1.9 dB
po16ac0_1 Reflection and attenuation
dcc po16ac4 Dcc1=1.1366, ac0 Dcc1=1.1300, ac0 comparison Dcc1=1.1300, ac4 Dcc1=1.1366, ac4