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n water

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n water

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  1. Example: 651 g ethylenglycol,HOCH2CH2OH, are dissolved into 1.5 x 103 g water (a 30.3% w/w, solution, commonly used as antifreeze agent in cars cooling systems). What is the vapor pressure of the water over the solution at 90°C? Suppose water behaves in an ideal fashion, the vapor pressure of pure water at 90°C is 525.8 mmHg, and the molar mass of ethylern glycol is 62.07 g. Data:651 grams solute, (HOCH2CH2OH), 1.5 x 103 g Solvent H2O, Vapor pressure at 90°C = 525.8 mm Hg Raoult’s law : P = csolvente Psolvente c solvent is unknown, we must calkculate it: csolvente = Solvent over the solution Análisis dimensional: nwater [ ] nwater = 1.50 x103 g 1 mole Water = 83.2 mol Nwater + nethylenglycol 18.02 g 1 mole ethylen glycol ] nethylenglycol = 651g [ = 10.5 mol 62.07 g cwater = 83.2 mole water = 0.888 83.2 mole water + 10.5 mole ethylen glycol P= 0.88 (525.8mm Hg) = 467 mm Hg *The units are correct for the sought variable

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