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网络知识微课系列（二）

网络知识微课系列（二）. 主题：二进制转换成十进制. 作者：欧阳俊 单位：广东省佛山市顺德区陈村职业技术学校. R 进位数制转换成十进制公式. 按基数 R 位权展开求和公式：. N R (a n a n-1 ‥‥ a 2 a 1 a 0 .a -1 a -2 ‥‥ a -m )=. ×R i. = a n × R n + a n-1 × R n-1 + ‥‥ + a 2 × R 2 + a 1 × R 1 + a 0 × R 0 .a -1 × R -1 a -2 × R -2 + ‥‥ + a -m × R -m. 整数部分. 小数部分.

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网络知识微课系列（二）

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  1. 网络知识微课系列（二） 主题：二进制转换成十进制 作者：欧阳俊 单位：广东省佛山市顺德区陈村职业技术学校

  2. R进位数制转换成十进制公式 按基数R位权展开求和公式： NR(anan-1‥‥a2a1a0.a-1a-2‥‥a-m)= ×Ri =an×Rn+an-1×Rn-1+‥‥+a2×R2+a1×R1+a0×R0.a-1×R-1 a-2×R-2+‥‥+a-m×R-m 整数部分 小数部分

  3. 二进制转换为十进制（整数部分） 整数部分转换 an×Rn+an-1×Rn-1+‥‥+a2×R2+a1×R1+a0×R0 例:(1 1 0 1 0 0 1 1.1101）2=（ ）10 • 1 0 1 0 0 1 1 位权 27 26 25 24 23 22 21 20 x x x x x x x x 求和 128 64 0 16 0 0 2 1 = = = = = = = = =（211）10 + + + + + + +

  4. 二进制转换为十进制（小数部分） a-1×R-1+a-2×R-2+‥‥+a-m×R-m 小数部分转换 例:(11010011.1 1 0 1）2=（ ）10 .1 1 0 1 位权 2-1 2-2 2-3 2-4 x x x x 求和 0.5 0.25 0 0.0625 = = = = =（0.8125）10 + + +

  5. 将整数部分与小数部分合在一起，即: • (11010011.1101）2 • 211 0.8125 • =(211.8125)10

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