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Term 3 Week 1-3; FSDr1,2,3 – Chapter 13 – Focus Study – Maths in Driving

Term 3 – Looking ahead. Term 3 Week 1-3; FSDr1,2,3 – Chapter 13 – Focus Study – Maths in Driving Week 4-7; MM1,2,3 – Chapter 2, 5, 9 – Units of Measurement and Applications; Applications of Perimeter, Area and Volume; Similarity and Right-Angle Triangles/Trigonometry

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Term 3 Week 1-3; FSDr1,2,3 – Chapter 13 – Focus Study – Maths in Driving

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  1. Term 3 – Looking ahead Term 3 Week 1-3; FSDr1,2,3 – Chapter 13 – Focus Study – Maths in Driving Week 4-7; MM1,2,3 – Chapter 2, 5, 9 – Units of Measurement and Applications; Applications of Perimeter, Area and Volume; Similarity and Right-Angle Triangles/Trigonometry Week 8 – Catch Up Week/Revision if time Week 9 – Exams Term 4 Week 1-2; Finish off the Preliminary Course (eg MM3 – Ch 9 - Similarity and Right-Angle Triangles/Trigonometry) Week 3 – HSC Course begins

  2. Write the heading!

  3. Write the heading! You need this FACT SHEET for these questions

  4. Write the heading & highlighted notes! The RTA is now know as the RMS: Stamp duty Link

  5. No notes to write here; read it as a class or individually

  6. No notes to write here; read it as a class or individually

  7. To Do:Ex 13A(p431) Q2, 3, 6, Q8 (pick 2 cars & 1 motorbike), Q9, 10, 11

  8. Write the heading! (a) I have borrowed 23.6 thousands, 23.6 x 20.76 = $489.94 To Do:Ex 13B (p436) Q1 (opt), 2, 3, 4, 6.

  9. Write the heading! View the linked Excel table: Fuel Running Costs (RACV) • Theory/Notes • Fuel Rates are calculated in: • km per Litre (km/L) or • Litres per km (L/km) or • Litres per 100km (L/100km)

  10. Ask: How far can it travel in 1L? Answer: 7.4 L / 100 km = = 100  7.4 = 13.5135… km on 1 Litre. So, if I have 48 L of petrol I can travel… Distance = 48 L  13.5135 km = 648.6 km (about 649 km) Ask: How much petrol does it take to travel in 1 km? To Do:Ex 13C (p437) Q1 (opt), 2, 4, 6, 8, 9, 10*, 11* * For students aspiring for a Band 6 in General Maths Answer: 11 L / 100 km = = 11  100 = 0.11 L for 1 km. So, if I have to travel 640 km I need… Distance = 640 km  0.11 L = 70.4 L

  11. Write the heading & the Theory. Fill in the table below from Ex 13D. THINK? Which car depreciates the least?

  12. Write the Example! Write the Theory. This formula is on the General Maths Formula Sheet

  13. Write the Example! To Do:Ex 13D (p441) Q2, 3, 4, 6, 8, 9 (Continued next slide)

  14. Write the Example 4. Note: A quicker way to the right hand column… Decreasing by 20% is the same as finding 80% of the amount. i.e. “ 0.8” Can you do this one? Watch my quick way on the calculator…

  15. Write the Theory. This formula is on the General Maths Formula Sheet To Do:Ex 13D (p443) Q12(opt),13,14,15,16,17, 21, 22, 23* see W.E.7 (p445-446) * For students aspiring for a Band 6 in General Maths

  16. Write the heading! Remember this table from earlier work linked Excel table: Fuel Running Costs (RACV)

  17. To Do:Ex 13E (p448) Q1-10, Q11-12* * For students aspiring for a Band 6 in General Maths

  18. Write the heading!

  19. This is NOT on your General Maths formula sheet and would need to be given in a question if it was asked about!

  20. Write this theory. These two formulas are on the General Maths Formula Sheet

  21. This is NOT on your General Maths formula sheet and would need to be given in a question if it was asked about! To Do:Ex 13F (p450) Q2 (a, c, e), 4(a, b), 7, 11, 12, 13, Q15* * For students aspiring for a Band 6 in General Maths

  22. Write the heading! To Do:Ex 13G (p454) Q1, 2, 3

  23. Write the heading! Write this theory. This formula Is on the General Maths Formula Sheet

  24. How far does the car travel before I put my foot on the brake? • D = S  T • D = 60 km/h  2.5 seconds • PROBLEM – THE UNITS ARE ALL DIFFERENT (eg Hours vs Seconds) • How many metres are in 1 km? • 1 km = 1000 metres, so 60 km/h is… • 60 km / h = 60 000 m / h. • How many seconds are in 1 hour? • 60  60 = 3600 seconds! • 60 km/h… Speed in metres per second is: 60 000 m / 3600 s… {calculate this…} • Speed (in m/s) = 16.7 m/s • NOW • D = S x T = 16.7 m/s  2.5 seconds • D = 41.7 metres • This is the distance I travel BEFORE I even realise there is a problem that I need to brake for. • It is called the reaction-time distance.

  25. From LAST SLIDE… These formulas are NOT on your General Maths formula sheet and would need to be given in a question if it was asked about.

  26. How far does the car travel before I put my foot on the brake? • D = S  T • D = 70 km/h  2.5 seconds • PROBLEM – THE UNITS ARE ALL DIFFERENT (eg Hours vs Seconds) • How many metres are in 1 km? • 70 km / h = 70 000 m / h. • How many seconds are in 1 hour? • 60  60 = 3600 seconds! • 70 km/h… Speed in metres per second is: 70 000 m / 3600 s… {calculate this…} • Speed (in m/s) = 19.4 m/s • NOW • D = 19.4 m/s  2.5 seconds • D = 48.6 metres • When I use the brakes how much distance is there until I stop (in dry conditions)? • Use d = 0.01v2 from your text/notes (for this formula you can keep the velocity in km/h) • d = 0.01  702 = 49 •  TOTAL DISTANCE = 48.6 metres + 49 metres = 97.6 metres! To Do:Ex 13H (p456) Q1(opt), 2, 4, 5, 7(opt), 8, 9(opt), 10, 11

  27. End of Focus Study topic!

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