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Presented by RAMA KRISHNA RAO AD KV, PICKET

Presented by RAMA KRISHNA RAO AD KV, PICKET . HEIGHTS & DISTANCES. REVISION.

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Presented by RAMA KRISHNA RAO AD KV, PICKET

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  1. Presented by RAMA KRISHNA RAO AD KV, PICKET HEIGHTS & DISTANCES

  2. REVISION

  3. QNo. From a point 100m above a lake , the angle of elevation of a stationary cloud is 300 and the angle of depression of reflection of the cloud in the lake is 600. Find the height of the cloud from the lake. Sol: E Let BC – surface of the lake A – point of observation AB = 100m ED = h (height of the cloud) h 300 A D 600 100m In rt. ∆EDA C B ---------(i) F

  4. In rt. ∆FDA E h 300 A D 600 100m C B F Hence, the height of the cloud from the surface of the lake = h + DC = 100 + 100 = 200m

  5. A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground. The angle of elevation of the balloon from the eyes of the girl at any instant is 60°. After some time, the angle of elevation reduces to 30°.Find the distance travelled by the balloon during the interval. Que: Sol: A E 88.2 m F D B 600 300 1.2 m C

  6. Let AC = 88.2m (height of the balloon from the ground) BC = 1.2m (height of the girl. AB = AC – BC = 88.2 – 1.2 = 87m A E In rt∆ ABD In rt∆ EFD 88.2 m F D B 600 300 BF = 100.34 m 1.2 m C The distance travelled by the balloon during the interval is 100.34m

  7. PRACTICE QUESTIONS

  8. Que 1: • From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometers stones on opposite sides of the aeroplane are found to be α and β. Show that height of the aeroplane is . • A man on deck of ship is 10m above water level. He observes that the angle of elevation of top of a hill is 600 and angle of depression of base of hill is 300. Calculate the distance of hill from ship and height of the hill. Que 2:

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