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A rod is bent into an eighth of a circle of radius a , as shown. The rod carries a total positive charge + Q uniformly distributed over its length. What is the electric field at the origin?. y. x. a.
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A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin? y x a
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin? y dq x a dE
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin? y d ds x a dE
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin? y dq x a dE
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin?
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin?
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. What is the electric field at the origin? You should provide reasonably simplified answers on exams, but remember, each algebra step is a chance to make a mistake.
What would be different if the charge were negative? What would you do differently if we placed a second eighth of a circle in the fourth quadrant, as shown? y x a
A rod is bent into an eighth of a circle of radius a, as shown. The rod carries a total positive charge +Q uniformly distributed over its length. A negative point charge -q is placed at the origin. What is the electric force on the point charge? Express your answer in unit vector notation. You could start with Coulomb’s Law, re-write it to calculate the dF on q1=-qdue to dq2 (an infinitesimal piece of the rod), and then integrate over dq2. In other words, do the whole problem all over again. y -q x Or you could multiply the two slides back by –q, simplify if appropriate, and be done with it. a
