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This article explains the fundamentals of organic chemistry mechanisms, focusing on the understanding of electron flow. Learn the steps involved in dehydration of alcohols and acid-catalyzed hydration reactions.
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Mechanisms Some Basic Orgo I Reactions
Understanding the basics… • Mechanisms are the most mind-boggling part of organic chemistry. • Students, generally speaking, have spent their time memorizing their way through science courses. • Mechanisms require a student to UNDERSTAND the fundamentals of electron flow…
Everyone knows that electrons are negatively charged. • Everyone knows that electrons are attracted to things with positive charges. • Yet, the understanding of a “mechanism” remains elusive to many students… • Let’s review the basics…
Electron flow is always from the electron-rich to the electron-poor species. • The electron-rich species is a Lewis Base (must have a lone pair) and is called the “nucleophile”. • The electron-poor species is a Lewis Acid (must have empty orbital) and is called the “electrophile”.
Examples of Nucleophiles: • Examples of Electrophiles:
SO – electron flow is always from nucleophile to electrophile, electron-rich to electron-poor… • Watch the direction of your arrows • from lone pairs to carbocation…
from anion to cation… • from anion to partial positive charge…
When working through a mechanism, the goal is NOT to memorize the steps of a mechanism of a SPECIFIC molecule. When you do that, typically you become too focused on the structures provided in a single example. • If that happens, you will get confused when the next mechanism problem has a DIFFERENT structure.
What you want to do is make a game plan - break down the steps of the mechanism, into little parts or steps. • The basic little steps are easier to remember. • By knowing the steps, you know how the mechanism progresses, regardless of the structure you are given to work with. • SO – break them down…
Dehydration of Alcohols Identify this mechanism – Starts with alcohol, ends with alkene… losing water… Dehydration, Acid-catalyzed… H+ from sulfuric or phosphoric acid…
Dehydration of Alcohols Steps Involved: • Convert –OH to H2O (use that acid!) • Loss of H2O and carbocation formation • Removal of H+, resulting in formation of pi bond to complete the conversion to alkene • E1 mechanism – think Zaitsev and Trans!
Dehydration of Alcohols Step 1: Convert –OH to H2O
Dehydration of Alcohols Step 2: Loss of H2O (“spontaneous dissociation”) to form carbocation
Dehydration of Alcohols Step 3: Removal of H+, resulting in formation of pi bond to complete conversion to alkene
Dehydration of Alcohols - Again Try another example: Alcohol to alkene (using acid) = dehydration (make water, lose water, form alkene)
Dehydration of Alcohols - Again Step 1: Convert –OH to H2O Remember the soul purpose for the acid is to turn the –OH into a water molecule. Now it wants to leave…
Dehydration of Alcohols - Again Step 2: Make the leaving group leave – “spontaneous dissociation” occurs:
Dehydration of Alcohols - Again Step 3: Form the pi bond, make an alkene Find the beta-H on the more substituted side (Zaitsev!)… use your water as a Lewis Base and pull that H+ off, forming a pi bond… Done!
Dehydration of Alcohols – And Again Try one more example: Do the steps… and check that your arrows and intermediates look like those you’re about to see…
Dehydration of Alcohols – And Again Step 1: Convert –OH to H2O Always draw the arrow from electron rich (lone pairs!) to electron poor (positive charge!)
Dehydration of Alcohols – And Again Step 2: Spontaneous Dissociation… Next step? Form the pi bond…
Dehydration of Alcohols – And Again Step 3: Form the pi bond, make an alkene Find the beta-H on the more substituted side that has an H… use your water and pull it off, forming a pi bond… Done!
Acid-Catalyzed Hydration Identify this mechanism – Starts with alkene, ends with alcohol…
Acid-Catalyzed Hydration Steps Involved: • Reaction of pi bond with H+ (acid catalyst!) resulting in Markovnikov carbocation formation • Addition of H2O (this is where the OH is coming from) • Removal of extra proton (H+) to finish formation of –OH.
Acid-Catalyzed Hydration Step 1: Reaction of pi bond with H+(acid cat.) resulting in Carbocation formation
Acid-Catalyzed Hydration Step 2: Addition of H2O
Acid-Catalyzed Hydration Step 3: Removal of extra proton (H+) to finish formation of –OH.
Acid-Catalyzed Hydration - Again Try Again… Identify the mechanism – alkene to alcohol, using acid and water…
Acid-Catalyzed Hydration - Again Step 1: React the pi bond with H+and form that carbocation: We don’t have to show this new H but make sure you are drawing the Markovnikov carbocation!
Acid-Catalyzed Hydration - Again Step 2: Add the H2O (the green H is still there, just didn’t show it in the second structure) Now - Finish it off… pull the extra proton…
Acid-Catalyzed Hydration - Again Step 3: Removal of extra proton (H+) to finish formation of –OH.
Acid-Catalyzed Hydration – And Again ‘Third time’s the charm”… Try one more example: Do the steps… and check that your arrows and intermediates look like those you’re about to see…
Acid-Catalyzed Hydration – And Again Step 1: React that nucleophilic pi bond with the proton H+: We don’t have to show this new H but make sure you are drawing the Markovnikov carbocation!
Acid-Catalyzed Hydration – And Again Step 2: Add the H2O Finish it off… pull the extra proton…
Acid-Catalyzed Hydration – And Again Step 3: Removal the extra proton (H+) to finish formation of –OH.
Addition of H-X Identify this mechanism – Starts with alkene, ends with single halide…
Addition of H-X Steps Involved: • Reaction of pi bond with H+ (of H-X), concurrent separation of X- , and formation of Markovnikov carbocation intermediate. • Attack on carbocation by X- to finish formation of product
Addition of H-X Step 1: Reaction of pi bond with H+ (of H-X), concurrent separation of X-, and formation of carbocation intermediate.
Addition of H-X Step 2: Attack of X- to finish formation of product.
Addition of H-X - Again Try it again… Identify the mechanism… Adding an Br and an H to an alkene…
Addition of H-X - Again Step 1: Reaction of pi bond with H+ (of H-X), concurrent separation of X-, and formation of carbocation intermediate.
Addition of H-X - Again Step 2: Attack of X- to finish formation of product.
Addition of HX – Once Again Try it again… Identify the mechanism… Adding a chloride (and an H, not drawn in) to an alkene…
Addition of HX – Once Again Step 1: React the pi bond with H+ (of H-X), separate off the X-, form the more substituted carbocation intermediate.
Addition of HX – Once Again Step 2: Attack of X- to finish formation of product.
Addition of X2 Identify this mechanism – Starts with alkene, ends with two halides…
Addition of X2 Steps Involved: • Attack by pi bond on polarized X-X with Halonium Ion formation • Attack of X- to pop open three-membered ring and finish formation of product.
Addition of X2 Step 1: Attack by pi bond on polarized X-X with Halonium Ion formation (and loss of X-)
Addition of X2 Step 2: Attack of X- to pop open three-membered ring and finish formation of product.