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Generalized Chebyshev polynomials and plane trees. Anton Bankevich St. Petersburg State University Jass’07. Chebyshev. Pafnuty Lvovich Chebyshev ( May 26, 1821 – December 8, 1894)
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Generalized Chebyshev polynomials and plane trees Anton Bankevich St. Petersburg State University Jass’07
Chebyshev Pafnuty Lvovich Chebyshev( May 26, 1821 – December 8, 1894) One of nine children, he was born in the village of Okatovo, the district of Borovsk, province of Kaluga into the family of landowner Lev Pavlovich Chebyshev.In 1832 the family moved to Moscow. In 1837 Chebyshev started the studies of mathematics at the philosophical department of Moscow University and graduated from the universityas “the mostoutstandingcandidate”. In 1847, Chebyshev defendedhisdissertation“Aboutintegrationwiththehelpoflogarithms”atSt Petersburg University. Chebyshev lectured at the university from 1847 to 1882. In 1882 he lefttheuniversityandcompletelydevotedhislifetoresearch. Chebyshev isknownforhisworkinthefieldofprobability, statisticsandnumbertheory. Chebyshev is considered to be one of the founding fathers of Russian mathematics. Among his students were Aleksandr Lyapunovand Andrey Markov
Chebyshev polynomials There exist a lot of definitions of Chebyshev polynomials. We shall now consider several of them.
Minimal norm Foranygivenn, amongthepolynomialsofdegreenwiththe leadingcoefficient1,Tn/2n-1 istheoneinwhichthemaximalabsolutevalueontheinterval [− 1,1] isminimal. Thismaximalabsolute valueis1/2n-1, and|Tn(x)|reachesthismaximumexactlyn + 1times: with x = −1, 1andwith theothern − 1extremalpointsoff. Chebyshev polynomialsareimportant inthe approximation theorybecausetheroots of the Chebyshev polynomials (whicharealsoreferred toas Chebyshev nodes)areusedasnodesinpolynomial interpolation.
Basis of the space of polynomials • Chebyshev polynomials appear to be an orthonormal basis for the space of polynomials in one variable with respect to the following scalar product. So, for any polynomial f(x) of degree n the coefficients in the formula can be found in the following way:
Composition • Th Chebyshev polynomials form an Abelian group with respect to the operation of composition
Generalizations • A lot of attempts were made to generalize the notion of Chebyshev polynomials. Polynomials in several variables
Motivation Let f(z) be a polynomial of degree n with complex coefficients Let us consider an inverse image of a random point w: Usually, this set consists of n distinct points. What is the minimal size of the inverse image of the point w? The answer is 1. The only examples are a +(b+cz)n.
Motivation And what is the minimal common size of the inverse image of two points w1and w2? The answer is n+1. But why?
Motivation But when does this degenerate case take place? What are the examples? An obvious example is a polynomial zn,where w1=0, w2 is a nonzero complex number. But there are some more examples. The other example is Tn(z) Chebyshev polynomials, where w1=-1, w2=1. It can be easily seen that the inverse image of these points is . But there are much more examples of this kind. And they are called generalized Chebyshev polynomials.
Definition A complex point z is called a critical point of polynomial f if f’(z)=0. A point w is called critical value of f if there exists a critical point z such that f(z)=w. Polynomial f(z) is called generalized Chebyshev polynomial (GCP) if it has at most two critical values. These polynomials are sometimes called Shabat polynomials
Certain properties of GCP The following can be easily seen: If f(z) is a GCP, then f(az+b) is GCP If f(z) is a GCP, then af(z)+b is GCP We shall call polynomials f and g equivalent if there exist constants a, b, A, B, such that: All the polynomials equivalent to certain GCP appear to be GCP too. So since this moment we shall observe only the polynomials with critical values equal to 0 and 1.
Geometric point of view Let us consider the inverse image of a segment. We colored the ends of the segment in black and white colors. Let [C0;C1] be the segment free of critical values of f. Then inverse image would be a set of disjoint sets, each of them being homeomorphic to a segment. f
Geometric point of view Then we suppose that there are no critical points inside a segment, but they may appear at one or both ends. Then some curvilinear segments may glue together with the monochrome vertexes. f
Inverse image of a segment But what picture can we see in the case where f is GCP? The answer is that we will see a bicolored plane tree It is a star for zn - and a chain for Chebyshev polynomials
Inverse image of a segment Th For each GCP f the inverse image of a segment is a bicolored plane tree. Proof: In case of existence of a circuit our polynomial g takes only real values on the boundary of domain bounded by our circuit.
Proof of theorem Then in case of existence of a circuit our polynomial g takes only real values on the boundary of domain bounded by our circuit. Then the harmonic function Im(g) equals zero on the boundary. But it means that Im(g)=0 on the whole domain, which is a contradiction.
The inverse theorem Th For each bicolored plane tree T there exists a GCP such that the corresponding inverse image is T. Moreover, this GCP is unique up to the equivalence introduced above.
Plane tree What is plane tree? • Plane tree is a picture of tree • Plane tree is a structure of a tree and for every vertex v a cyclic order on the vertices adjacent to v.
Canonical geometric form For each bicolored plane tree, there exists a GCP. And we have presented a way to construct a geometrical form from the GCP. So for each tree we can construct its canonical geometric form. Once more:
Construction of GCP The next question is: Given a tree, how can we construct a polynomial? The first way is to write a system of equations: αi and βi are the degrees of black and white vertices of the graph. Now we have n algebraic equations in n+2 variables. This is sufficient to construct the polynomial.
Tree families While constructing our GCP, we only used αi and βi, which are the degrees of black and white vertices of the graph. But for each multiset of degrees there are a lot of trees with the same multisetset. All such trees form a family <α, β>, where α=(α1, α2, …αk), β =(β1, β2, … βn+1-k). By solving the equations from the previous slide we can find all the polynomials which correspond to the trees of this family.
Computation of GCP The computation of coefficients of GCP for a tree with a big number of vertices becomes a complicated problem since we have to solve a system of algebraic equations of a high degree, so another way had to be found and it has been found. The idea of the new method is the following: First we calculate coefficients not precisely. It can be done by using the class of polynomials with the following conditions: There exist complex numbers C and w such that g(w) = C, f’(w)=0, f’’(w)≠0 If f’(z) = 0, then f(z) =±1 or z = w In the second step we calculate precise values of the coefficients.
Galois group action on trees It can be easily seen that the group Gal(Q/Q) acts on the set of Chebyshev polynomials with algebraic coefficients. So we can define an action of Gal(Q/Q) of bicolored plane trees. This leads us to the definition of the field of definition of a tree: this is a field which corresponds to the subgroup of Gal(Q/Q) that fixes the given tree.
GCP coefficients But what is the connection between the field of definition and generalized Chebyshev polynomials? The answer is given in the following theorem: Th For any bicolored plane tree there exists a generalized Chebyshev polynomial whose coefficients belong to the field of definition of the tree.
Orbits vs families It can be easily seen that the action of Galois group on the tree does not change the multiset of valences of the tree. So the orbit of a tree is a subset of its family. But do they coincide? The answer is: not always.
Composition of polynomials It is well known that the composition of Chebyshev polynomials is Chebyshev polynomial, too. And is this the case for generalized Chebyshev polynomials? Th Let f, g be GCP such that {f(0), f(1)} lie in {0, 1}. Then the composition f(g(x)) is also GCP.
Composition of trees Let us imagine that we have two trees T1 and T2. Their polynomials are f1 and f2. And we need to construct a tree which corresponds to f1◦f2. Do we have to calculate f1 and f2, find their composition and then construct a tree or there is a direct way?
Composition of trees head body tail
Plane maps: Belyi functions Till this moment we have been talking about plane trees, but what about plane maps? • Let f be a rational function on the Riemann sphere that satisfies the following conditions: • f has only three critical values: 0, 1, infinity • All points of f-1(1) are critical with the degree exactly equal to 2. Such functions are called Belyi functions.
Plane maps: map construction But how are Belyi functions connected with maps? f-1(∞) are vertices. f-1(1, ∞) are edges ( f-1(1) are points on edges ) f-1(0) are faces