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Solving Proportions: Simple and Complex Problems

This chapter focuses on solving simple and complex proportion problems. Learn how to find missing values using multiplication and solve problems involving fractions, decimals, and percents.

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Solving Proportions: Simple and Complex Problems

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  1. Chapter 5: Proportions

  2. Question Solve the proportions: 3 : 12 :: 4 : x multiply the means and extremes x = 16 10 : 100 :: x : 20 multiply the means and extremesx = 2

  3. Solving a Simple Proportion Problem • Multiply the extremes. • Multiply the means. a : b :: c: d

  4. Objectives • Solving simple proportion problems • Solving proportion problems involving fractions, decimals, and percents

  5. Proportions (con’t) • A proportion sets two ratios equal to each other. In one ratio, one of the quantities is not known. You then use multiplication and solve the equation for the missing value. Example: 6 : 10 :: 3 : 5 Proportions

  6. The first and fourth terms are the extremes. • The second and third terms are the means. Example: 6 : 10 :: 3 : 5 10 3 = 30, product of the means 6 5 = 30, product of the extremes

  7. Proportions • Suppose it takes 48 chicken fingers to feed Mr. Young’s 4th grade class of 20 students. How many chicken fingers would be needed for 30 students? • 48 CF : 20 kids :: x CF : 30 kids • (48CF) (30 kids) = (xCF)(20 kids) • 20x = 1440 • x = 72 chicken fingers

  8. Solve the following Proportion Problem Involving Fractions Example: : :: x : 25 x = 62.5

  9. Solving a Proportion Problem Involving Decimals Example: 0.6 : 0.12 :: 0.2 : x x = 0.04

  10. Solving a Proportion Problem Involving Fractions and Percents Example: 2/3% : 1/5 :: 50 : x x = 1500

  11. Assignment • Complete Ch 5 worksheet 1-30

  12. Assignment • Ch 5 Proportions word problems

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