130 likes | 300 Views
VECTOR RESOLUTION answers. Q1. Horizontal component = 10 cos 30o Verical component = 10 sin 30o. Q2. Sum of forward force = 5 cos 30o + 7 =11.3 N. Q3. Resultant force on car (parallel to the slope) = 10 000 cos 60o – 2000 = 3000 N (downwards). Q4. Resultant force
E N D
Q1 Horizontal component = 10 cos 30o Verical component = 10 sin 30o
Q2 Sum of forward force = 5 cos 30o + 7 =11.3 N
Q3 Resultant force on car (parallel to the slope) = 10 000 cos 60o – 2000 = 3000 N (downwards)
Q4 Resultant force = 700 cos 20o – 500 = 158 N (upwards)
q5 • Draw free body diagram R f W = 5.0 N
30o Guided Practice • Choose suitable perpendicular axes y R f x W = 5.0 N You may also choose horizontal and vertical axis but realize that you will then have to resolve more forces and the acceleration as well.
Guided Practice • Resolve all forces along both axes Wx = 5.0 sin 30o = 2.5 N Wy = 5.0 cos 30o = 4.3 N y R f Wx Wy x
Guided Practice • Solve the problem • Ball is in equilibrium along y-axis. If not, it will move away from the surface. Σ Fy = 0 R – Wy = 0 R = Wy = 4.3 N Upwards, normal to the surface
Guided Practice (b) Ball is accelerating along x-axis. Use Newton’s second law. Σ Fx = ma Wx – f = ma 2.5 – 2.0 = 0.50a a = 1.0 ms-2 in the positive x-direction