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Limiting Reactants and ICE Charts

Limiting Reactants and ICE Charts. “Chemistry” Salami Sandwiches Question: If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how many salami sandwiches can you make? Answer : Give reasons. Chemistry Cake. Chemistry Cake

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Limiting Reactants and ICE Charts

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  1. Limiting Reactants and ICE Charts

  2. “Chemistry” Salami Sandwiches Question: If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how many salami sandwiches can you make? Answer: Give reasons

  3. Chemistry Cake

  4. Chemistry Cake You have 20 cups of flour, 8 cups of sugar, 30 litres of milk and 48 eggs in your kitchen. The recipe for chemistry cake is:

  5. Chemistry Cake You have 20 cups of flour, 8 cups of sugar, 30 litres of milk and 48 eggs in your kitchen. The recipe for chemistry cake is: 3 cups of flour 2 cups of sugar 2 litres of milk + 6 eggs = 1 chemistry cake

  6. How many cakes can you make?

  7. How many cakes can you make? • Which ingredient ran out first and limited the number of cakes you could make?

  8. How many cakes can you make? • Which ingredient ran out first and limited the number of cakes you could make? • What and how much of each ingredient is left over?

  9. How many cakes can you make? • Which ingredient ran out first and limited the number of cakes you could make? • What and how much of each ingredient is left over? • What does this assignment have to do with chemistry?

  10. Limiting Reactant Problems

  11. In the chemical reaction: 2 Al + 3 Br2 2 AlBr3

  12. In the chemical reaction: 2 Al + 3 Br2 2 AlBr3

  13. In the chemical reaction: 2 Al + 3 Br2 2 AlBr3 2 moles of Al require 3 moles of Br2 to produce 2 moles of AlBr3

  14. In the chemical reaction 2 Al + 3 Br2 2 AlBr3 2 moles of Al require 3 moles of Br2 to produce 2 moles of AlBr3 What if Al and Br2 are not present in a perfect 2 : 3 ratio?

  15. Answer:

  16. Answer: One reactant runs out:

  17. Answer: One reactant runs out: There is a reactant left over:

  18. Answer: One reactant runs out: Limiting Reactant There is a reactant left over:

  19. Answer: One reactant runs out: Limiting Reactant There is a reactant left over: Excess Reactant

  20. Answer: One reactant runs out: Limiting Reactant There is a reactant left over: Excess Reactant We use an ICE chart to find out how much reactant in excess is left over and how much product is produced.

  21. Answer: One reactant runs out: Limiting Reactant There is a reactant left over: Excess Reactant We use an ICE chart to find out how much reactant in excess is left over and how much product is produced. I = Initial moles (unreacted reactants)

  22. Answer: One reactant runs out: Limiting Reactant There is a reactant left over: Excess Reactant We use an ICE chart to find out how much reactant in excess is left over and how much product is produced. I = Initial moles (unreacted reactants) C = Change in moles (reactants consumed & products produced)

  23. Answer: One reactant runs out: Limiting Reactant There is a reactant left over: Excess Reactant We use an ICE chart to find out how much reactant in excess is left over and how much product is produced. I =Initial moles (unreacted reactants) C = Change in moles (reactants consumed & products produced) E = End moles

  24. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made.

  25. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO

  26. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I C E Write down the INITIAL moles given in the question. If grams given we need to convert to moles.

  27. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E

  28. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E Now CALCULATE the moles of each reactant needed for the reaction. Start with whichever element you want.

  29. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E 12.0 mol O2

  30. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E 12.0mol O2 x 2 mol Ca 1 mol O2

  31. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E 12.0 mol O2 x 2 mol Ca = 24.0 mol Ca 1 mol O2

  32. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E 12.0 mol O2 x 2 mol Ca = 24.0 mol Ca 1 mol O2 Don’t have enough Ca! 

  33. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C E 12.0 mol O2 x 2 mol Ca = 24.0 mol Ca 1 mol O2 Don’t have enough Ca !  12.0 mol Ca x 1 mol O2 = 6.00 mol of O2 2 mol Ca Yahooooo!  Enough O2 !!! This means for all 12 moles of Ca to be used up we need 6 moles of O2.

  34. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol E

  35. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol E Since the limiting reagent determines how much product is formed we use the moles of limiting reagent to determine the moles and mass of product

  36. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol E 12.0mol Ca

  37. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol E 12.0mol Ca x 2 mol CaO 2 mol Ca

  38. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol E 12.0mol Ca x 2 mol CaO= 12.0 mol CaO 2 mol Ca

  39. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C 12.0 mol 6.0 mol 12.0 mol E

  40. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E Now complete the ICE chart by filling in the END amounts of each species.

  41. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E 0 mol

  42. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E 0 mol 6.0 mol

  43. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E 0 mol 6.0 mol 12.0 mol

  44. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E 0 mol 6.0 mol 12.0 mol Limiting Reactant

  45. 12.0 mole Ca and 12.0 mole O2 react. Find the limiting reactant, the amount of excess reactant and the amount of product made. 2 Ca + 1 O2 2 CaO I 12.0 mol 12.0 mol 0 C -12.0 mol -6.0 mol +12.0 mol E 0 6.0 mol 12.0 mol Limiting Excess Reactant Reactant

  46. 24.0 mole of Al reacts with 24.0 mol of Br2. Find the limiting reactant, the amount of the excess reactant and the amount of product made.

  47. 24.0 mole of Al reacts with 24.0 mol of Br2. Find the limiting reactant, the amount of the excess reactant and the amount of product made. 2 Al + 3 Br2 2 AlBr3

  48. 24.0 mole of Al reacts with 24.0 mol of Br2. Find the limiting reactant, the amount of the excess reactant and the amount of product made. 2 Al + 3 Br2 2 AlBr3 I C E Write down the INITIAL amounts given in the question

  49. 24.0 mole of Al reacts with 24.0 mol of Br2. Find the limiting reactant, the amount of the excess reactant and the amount of product made. 2 Al + 3 Br2 2 AlBr3 I 24.0 mol 24.0 mol 0 mol C E

  50. 24.0 mole of Al reacts with 24.0 mol of Br2. Find the limiting reactant, the amount of the excess reactant and the amount of product made. 2 Al + 3 Br2 2 AlBr3 I 24.0 mol 24.0 mol 0 mol C E Now CALCULATE the moles of each reactant needed for the reaction. Start with whichever element you want.

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