1 / 1

Mg (s) + ½O 2(g) → MgO (s) D H= _____

key. Names: ___________________________________. All encompassing activity…A.P. Chemistry Ch. 6. -626 kJ. Mg (s) + ½O 2(g) → MgO (s) D H= _____. MgO (s) + 2HCl (aq) → MgCl 2(aq) + H 2 O (l) D H = _______. -100 kJ. flipped. Add these steps:.

xaviera-camacho
Download Presentation

Mg (s) + ½O 2(g) → MgO (s) D H= _____

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. key Names: ___________________________________ All encompassing activity…A.P. Chemistry Ch. 6 -626 kJ Mg(s) + ½O2(g) → MgO(s)DH= _____ MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l) DH = _______ -100 kJ flipped Add these steps: Mass of MgO = 0.50 g (0.013 mol)←L.R. Volume of HCl = 50.0 mL (3.0 M) DT = 6.3° C (typical temperature change with the amounts used) qwater = (50.0 g)(4.184 J/g°C)(6.3°C) = 1318 J qsys = -1318 J DHrxn= -1318 J/ 0.013mol = -1.0 x 105 J/mol 100 kJ MgCl2(aq) + H2O(l) → MgO(s) + 2HCl(aq)DH = Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)DH = -440 kJ -286 kJ H2(g) + ½O2(g) → H2O(l)DH= Mg(s) + ½O2(g) → MgO(s)DH= _____ -626 kJ Of Note: the accepted value for the heat of formation of MgO is -602kJ…if you don’t believe me look it it up H2(g) + ½O2(g) → H2O(l)DH= _____ -286 kJ Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) DH = _______ -440 kJ Mass of Mg = 0.50 g (0.021 mol)←L.R. Volume of HCl = 50.0 mL (3.0 M) DT = 44.2° C (typical temperature change with the amount that used) qwater= (50.0 g)(4.184 J/g°C)(44.2°C) = 9240 J qsys= -9240 DHrxn= -9240 J/ 0.021mol = -440,000 J/mol

More Related