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COMP313A Programming Languages

COMP313A Programming Languages. Logic Programming (3). Lecture Outline. Some Prolog Unification. Some more prolog. Recursive rules example predecessor relation predecessor(X,Z) :- parent(X,Z). predecessor(X,Z) :- parent(X,Y), parent(Y,Z) And so on…

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COMP313A Programming Languages

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  1. COMP313A Programming Languages Logic Programming (3)

  2. Lecture Outline • Some Prolog • Unification

  3. Some more prolog • Recursive rules example predecessor relation predecessor(X,Z) :- parent(X,Z). predecessor(X,Z) :- parent(X,Y), parent(Y,Z) And so on… predecessor(X,Z) :- parent(X,Y), predecessor(Y,Z).

  4. Some more prolog parent(pam,bob). parent(tom,bob). parent(tom,liz). parent(bob, ann). parent(bob, pat). parent(pat, jim). ? predecessor(pam,bob). ? predecessor(pam, ann). ? predecessor(pam, liz). ? predecessor(pam, X).

  5. A prolog program comprises clauses - facts, rules and queries PROGRAM big(bear). %clause 1 big(elephant). %clause 2 small(cat). %clause 3 brown(bear). %clause 4 black(cat). %clause 5 grey(elephant). %clause 6 dark(Z) :- black(Z). %clause 7 dark(Z) :- brown(Z). %clause 8 ?dark(X), big(X).

  6. Data ObjectsAtoms versus numbers versus Variables • Atoms • strings of letters, digits, and the underscore character beginning with a lower case letter • some strings of special characters • can enclose strings of characters in single quotes e.g. ‘Fred’ • Numbers • integers and floats

  7. Data ObjectsAtoms versus Variables • Variables are strings of characters, digits and underscores that begin with an uppercase letter or an underscore • Can use the anonymous underscore hasachild(X) :- parent(X,Y) hasachild(X) :- parent(X,_) ? parent(X, _)

  8. Data ObjectsStructured objects • objects that have several components location(X, Y, Orientation). location(156, 786, 25). location(156, 786, Orientation). location is the functor

  9. Structures date(X,Y,Z). date(20, june, 2005). date(Day, june, 2005). date(Day, Month, Year) :- Day > 0, Day <= 31,…….

  10. data objects structures simple objects constants variables atoms numbers These are all terms

  11. Operations on listsMembership • The member relation member(X,L) ? member(d, [a, b, h, d]). ? ? member(d, [a,b,[d h], e]). ? ?member([d, h], [a, [d,h], e f]). ?

  12. Membership • X is a member of L if • X is the head of L, or • X is a member of the tail of L. member(X, [X|Tail]). member(X, [Head | Tail]) :- member(X,Tail). Note two separate clauses

  13. Membership • X is a member of L if • X is the head of L, or • X is a member of the tail of L, or • X is a member of a sublist of L member(X, [X|Tail]). member(X, [Head | Tail]) :- member(X,Tail). plus one more clause……

  14. Concatenation • The concatenation relation – conc(L1, L2, L3) ? conc([a,b], [c,d], [a,b,c,d]) yes ? conc([a,b], [c,d], [a, b, [c,d]]) no ?conc([a,b], [c,d], X). X = [a,b,c,d]

  15. Concatentation • conc(L1, L2, Result) • If L1 is the empty list • then L2 and Result must be equal • If L1 is nonempty • then have [X|L1tail] • recursively X becomes the head of Result and we use conc to find the tail of result [X|TailResult] • Eventually will have exhausted L1 and TailResult will be L2.

  16. Concatentation conc([], L, L). conc([X | L1], L2, [X | L3]) :- conc(L1, L2, L3).

  17. Unification • Matching clauses with variables • Have to find the appropriate substitutions for variables so that the clauses match • Process is called unification • Process by which variables are instantiated

  18. GCD example gcd(u,0,u) gcd(u,v,w) Ü not zero(v), gcd(v, u mod v, w) Using resolution the goal Ü gcd(15, 10, x)

  19. Unification in Prolog • A constant unifies only with itself ? me = me. Yes ?me = you. No Gcd(5, 0, 5) Ü Gcd(5, 0, 5) Gcd(5, 10, w) Ü Gcd(5, 0, w)

  20. Unification in Prolog… • A variable that is uninstantiated unifies with anything and becomes instantiated with that thing ? me = X. X = me ? f(a,X) = f(Y, b). X = b Y = a ? f(X) = f(Y) gcd(u,v,w) Ü not zero(v), gcd(v, u mod v, w), gcd(15, 10, x). gcd(15, 10, x) Ü not zero(10), gcd(10, 15 mod 10, x), gcd(15, 10, x).

  21. Unification in Prolog • A structured term (predicate or function applied to arguments requires • Same predicate/function name • Same number of arguments • Arguments can be unified recursively ? f(X) = g(X) ? f(X) = f(a,b) ? f(a, g(X)) = f(Y, b) ? f(a, g(X)) = f(Y, g(b))

  22. Unification examples • Unify the following : p(X,Y) and p(a, Z) p(X,X) and p(a,b) ancestor(X,Y) and ancestor(bill, W) p(X,a,Y) and p(Z,Z,b) p(Marcus, g(X,Y)) and f(x, g(Caesar, Marcus)) g(X, X) and g(f(X), f(X))

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