1 / 31

WELCOME! 1. Grab the materials in your folder . 2. Take out your homework packet .

WELCOME! 1. Grab the materials in your folder . 2. Take out your homework packet. Small Business. No Trash No Detention Bonus Homework Science Fair. 80%. How does a battery work?. MAD Skillz : Writing electrons in equations.

yama
Download Presentation

WELCOME! 1. Grab the materials in your folder . 2. Take out your homework packet .

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. WELCOME! 1. Grab the materials in your folder. 2. Take out your homework packet.

  2. Small Business • No Trash No Detention Bonus • Homework • Science Fair

  3. 80%

  4. How does a battery work?

  5. MAD Skillz: Writing electrons in equations • Think of half reactions as money (electrons) in an Easter egg (atom). • If you gain an electron the money is outside the egg at first, then goes inside. • If you lose an electron, the money is in the egg at first, the goes outside Write the formula for Mg losing two electrons.

  6. MAD Skillz: Writing electrons in equations • Think of half reactions as money (electrons) in an Easter egg (atom). • If you gain an electron the money is outside the egg at first, then goes inside. • If you lose an electron, the money is in the egg at first, the goes outside Write the formula for Cl gaining an electron

  7. Concentrations • If an element gains an electron then it goes through ___________________ • If an element loses and electron then it goes through ___________________

  8. Chem-mem-tip OIL - _________________ _________________ _________________ RIG - _________________ _________________ _________________

  9. Classify the following reaction as either an oxidation or reduction half reaction.

  10. Electrical Current • To measure electrical current use _______________ (V)

  11. MAD Skillz: Convert large numbers in scientific notation • Goal: Make sure the number of electrons on each side of the equation is balanced. • If you need to flip an equation, invert the charge (e.g., positive goes to negative) • If you need to multiply a side, multiply the entire half reaction by the number. • DO NOT MULTIPLY THE VOLTAGE • Cancel out the electrons and drop the remaining elements in the final reaction. • Add the final voltage together • Hint: YOU CANNOT HAVE A NEGATIVE VOLTAGE! Mg2+(aq) + 2e- Cr(s) -2.37V + Na+(aq) + e- Na(s) -2.71V _______________________________________

  12. Guided Practice Clickers

  13. What is the correct formatting for Sulfur gaining one electron? • S + e-  S- • S  S- + e- • S + e-  S+ • S  S+ + e-

  14. What is the correct formatting for Nitrogen losing two electrons? • N +2e-  N2- • N  N2- +2e- • N + 2e-  N2+ • N  N2+ + 2e-

  15. What is the correct formatting for Iron losing three electrons? • Fe +3e-  Fe3- • Fe  Fe3- +3e- • Fe + 3e- FeE+ • Fe  Fe3+ + 3e-

  16. What is oxidation? • Gain of electrons • Loss of electrons • Termination of electron • A mystical rapper from Nigeria

  17. What is the tip to remember what Oxidation and Reduction is? • OIL RIG • OIG RIL • OR IL II • OMG

  18. Is the following half reaction an oxidation or reduction reaction • Oxidation • Reduction

  19. Why is the following equation an reduction reaction • It lost an electron • It gained an electron • It terminated an electron • It changed a proton into an electron

  20. Why is the following equation an oxidation reaction • It lost an electron • It gained an electron • It terminated an electron • It changed a proton into an electron Sn(s)  Sn2+ + e-

  21. Classify the following reaction as either oxidation or reduction. Describe why. • Oxidation because it gained an electron • Reduction because it gained an electron • Oxidation because it lost an electron • Reduction because it lost an electron

  22. When you add two half reactions to determine voltage, what is your primary goal to solve the problem • Have equal number of electrons in the products and reactants • Have electrons in the products and reactants • Add the equations • Add the voltages

  23. When adding these two half reactions which equations should be flipped and which should be multiplied? • Flip the bottom and invert the voltage • Flip the bottom and keep the voltage the same • Flip the top and and invert the voltage • Flip the top or bottom as long as the voltage also flips • Sn2+(aq) + 2e- -> Sn(s) -0.14V • + Mn2+(aq) + 2e- -> Mn(s) -1.18V _______________________________________

  24. When adding these two half reactions which equations should be flipped and which should be multiplied? • Flip the bottom and invert the voltage • Flip the bottom and keep the voltage the same • Flip the top and and invert the voltage • Flip the top or bottom as long as the voltage also flips • Ti+(aq) + e- -> Ti(s) -0.34V • + Rb+(aq) + e- -> Rb(s) -2.92V • _______________________________________

  25. When adding these two half reactions which equations should be flipped and which should be multiplied? • Flip the bottom and multiply the bottom • Flip the bottom and multiply the top • Flip the top and multiply the top • Flip the top and divide the bottom Mg2+(aq) + 2e- Cr(s) -2.37V + Na+(aq) + e- Na(s) -2.71V _______________________________________

  26. When adding these two half reactions which equations should be flipped and which should be multiplied? • Flip the bottom and multiply the bottom • Flip the bottom and multiply the top • Flip the top and multiply the top • Flip the top and multiply the bottom Cu+(aq) +e- Cu(s) 0.52V + Sn2+(aq) +2e- Sn(s) -0.14V _______________________________________

  27. Cu+(aq) +e- Cu(s) 0.52V + Sn2+(aq) +2e- Sn(s) -0.14V _______________________________________

  28. Cr3+(aq) + 3e- Cr(s) -0.74V + Fe2+(aq) + 2e- Fe(s) -0.44V _______________________________________

More Related