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Engineering Orientation

Engineering Orientation. Engineering Economics. Engineering Economics. Value and Interest Cost of Money Simple and Compound Interest Cash Flow Diagrams Cash Flow Patterns Equivalence of Cash Flow Patterns. Value and Interest. Money, Amount vs. Value

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Engineering Orientation

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  1. Engineering Orientation Engineering Economics

  2. Engineering Economics • Value and Interest • Cost of Money • Simple and Compound Interest • Cash Flow Diagrams • Cash Flow Patterns • Equivalence of Cash Flow Patterns

  3. Value and Interest • Money, Amount vs. Value • First Cost is what you pay for an item when you buy it

  4. http://en.wikipedia.org/wiki/Time_value_of_money • The time value of money is the value of money with a given amount of interest earned or inflation accrued over a given amount of time. • The ultimate principle suggests that a certain amount of money today has different buying power than the same amount of money in the future. • $100 of today's money invested for one year and earning 5% interest will be worth $105 after one year.

  5. Interest / Interest Rate • The difference between the anticipated amount in the future and its current value is called interest. • At an annual interest rate of 10% what is the value now of the expectation of receiving $1 in one year?

  6. Cost of Money • Interest that could be earned if the amount invested in a business or security was instead invested in government bonds or in time deposit.

  7. Cost of Money • Buy a car for $20,000 of your own cash vs. US bonds returning 5%/yr ($1,000 forever) • In effect you are paying $1,000 for ever

  8. Simple and Compound Interest • You have a business project costing $100,000 • You get a loan for 7.5% yearly for 5 years at simple interest payable at the end of the loan • The loan costs $7,500 for each of five years for a total interest of $37,500 • Total cost over 5 years = $137,500

  9. Simple and Compound Interest • In the previous example, are you borrowing? • $7,500 for four years, • $7,500 for three years, • $7,500 for two years, • $7,500 for one year

  10. Formulae • P or PV Principal is the amount borrowed • N # of pay periods • i Interest rateper period • F or FV, Future worth, value in the future of what you have to payback • Formulae: • Simple interest = P(1 + Ni) ( = $137,500) • Compound interest = P(1 + i)N ( = $143,563)

  11. Pay periods • Calculate FV • Assume your loan is compounded quarterly, monthly or daily instead of yearly. • Student loan of $25,000 at 8% for • Annually for two years, • Quarterly for two years and • Daily for two years

  12. Pay periods

  13. Continuous Interest Rate • Compute the effective annual interest rate ie equivalent to 8% nominal annual interest compounded continuously. • Calculate the FV • In the limit

  14. Compare

  15. Example • What amount must be paid in two years to settle a current debt of $1,000 if the interest rate is 6% Annually? • PV = 1,000 • i = .06 • N = 2 • n = 1

  16. Cash Flow Diagrams

  17. Cash Flow Patterns

  18. Example • A new widget twister, with a life of six years, would save $2,000 in production costs each year. Using a 12% interest rate, determine the highest price that could be justified for the machine. Although the savings occur continuously throughout each year, follow the usual practice of lumping all amounts at the ends of years.

  19. Example • A new widget twister, with a life of six years, would save $2,000 in production costs each year. Using a 12% interest rate, determine the highest price that could be justified for the machine. Although the savings occur continuously throughout each year, follow the usual practice of lumping all amounts at the ends of years.

  20. Example • How soon does money double if it is invested at 8% interest?

  21. Example • Compute the annual equivalent maintenance costs over a 5-year life of a laser printer that is warranted for two years and has estimated maintenance costs of $100 annually. Use i = 10%.

  22. Return on Investment • ROI = The ratio of annual return to the cost of the investment • If an investment of $500,000 produces an income of $40,000 per year, its ROI = $40,000/$500,000 = 0.08 = 8%. • Many successful large companies operate with ROI’s of 15% or more

  23. Return on Investment

  24. Cost of losing one semester • Two students, Frank and Mary start they Engineering Studies on the same date and they make the commitment of retiring thirty years after their forecasted graduation date (the date they would graduate if no delays are introduced). This date will not change if any delays make any of them graduate later. • Calculate the difference in their earnings if for some reasons Frank is required to graduate one semester later than what was intended.

  25. The Model • Assumptions: • We have a constant inflation • You have a yearly Salary Increase greater than what you loose because of inflation • Salary increases and inflation are constant • They work for the same company their entire carrier

  26. One year window

  27. Four year window

  28. Thirty year window

  29. Engineering Economics • Value and Interest • Cost of Money • Simple and Compound Interest • Cash Flow Diagrams • Cash Flow Patterns • Equivalence of Cash Flow Patterns

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