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9! = 9 • 8 • 7 • 6 • 5 • 4 • 3 • 2 • 1 = 362,880. Simplify. COURSE 3 LESSON 11-2. Permutations. A CD has nine songs. In how many different orders could you play these songs?. The songs can be played in 362,880 different orders or permutations. 11-2.
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9! = 9 • 8 • 7 • 6 • 5 • 4 • 3 • 2 • 1 = 362,880 Simplify. COURSE 3 LESSON 11-2 Permutations A CD has nine songs. In how many different orders could you play these songs? The songs can be played in 362,880 different orders or permutations. 11-2
Write the notation as a product of 5 factors, starting with 11. 11P5 = 11 • 10 • 9 • 8 • 7 = 55,440 Simplify. COURSE 3 LESSON 11-2 Permutations Simplify 11P5. There are 55,440 permutations of 11 items chosen 5 at a time. 11-2
Enter 15. Find the menu. Select nPr . COURSE 3 LESSON 11-2 Permutations In a spelling contest, trophies are given for first, second, and third places. There are 15 finalists in the contest. How many different arrangements are possible for the winners of the trophies? Use a calculator. Enter 3. The display shows 2730. There are 2,730 arrangements for the three winners. 11-2
COURSE 3 LESSON 11-2 Permutations 1. In how many different ways can you line up a half dollar, quarter, dime, nickel, and penny? 2. A CD has 11 songs. Find in how many orders you can play the songs. 3. Simplify 10P3. 120 39,916,800 720 11-2