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x 3. q. x 3. x 1. x 2. VIII.3-1 Timoshenko Beams (1). In both beam theory, only stress resultants (sum over cross section area) are considered. 3D problems 1D problems !!. Elementary beam theory (Euler-Bernoulli beam theory). Timoshenko beam theory.
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x3 q x3 x1 x2 VIII.3-1 Timoshenko Beams (1) In both beam theory, only stress resultants (sum over cross section area) are considered. 3D problems 1D problems !! Elementary beam theory (Euler-Bernoulli beam theory) Timoshenko beam theory • A plane normal to the beam axis in the undeformed state remains normal in the deformed state. Assume: r b=0 symmetric axis • A plane normal to the beam axis in the undeformed state remains plane in the deformed state. • All the points on a normal cross-sectional plane have the same transverse displacement. • There is no stretch along the beam axis. no thickness stretch neglect shear deformation!!
x3 q x3 x1 x2 B.C. VIII.3-2 Timoshenko Beams (2) prismatic beam: n1 = 0: = equations of equilibrium: symmetric axis strain field: stress field: Ok!! geometry, loading: symmetric w.r.t. x3-axis s12 odd function of x2
VIII.3-3 Timoshenko Beams (3) Summary: prismatic beam: n1 = 0: =
Approximations: • Neglect VIII.3-4 Timoshenko Beams (4) • Replace m by 2m • : shear factor, a correction factor is used to adjust the approximate theory to agree with the 3D theory. When n = 0.3, = 0.850 for rectangular cross-section and 0.886 for circular cross-section. Timoshenko beam equation
VIII.3-5 Remarks • Euler-Bernoulli beam theory neglects shear deformation • The Timoshenko beam theory accounts for flexural as well as shear deformation. While the Euler-Bernoulli beam theory accounts only for flexural deformation. • Two B.C.s are required at both ends • either w or Q • either dw/dx1 or M
x3 q x1 L B.C.s: VIII.3-6 Example (1) cross-sectional area A moment of inertia I correction factor
B.C.s: VIII.3-7 Example (2)