100 likes | 287 Views
PDT 180 ENGINEERING SCIENCE. Vectors And Scalars (Continue). Projectile Motion. A projectile is an object moving in two dimensions under the influence of Earth's gravity . Its path is a parabola. Neglect air resistance. Consider motion only after release and before it hits.
E N D
PDT 180ENGINEERING SCIENCE Vectors And Scalars (Continue)
Projectile Motion • A projectile is an object moving in two dimensions under the influence of Earth's gravity. • Its path is a parabola.
Neglect air resistance. • Consider motion only after release and before it hits. • Analyze the vertical and horizontal components separately (Galileo). • No acceleration in the horizontal, so velocity is constant. • Acceleration in the vertical is – 9.8 m/s2 due to gravity and thus velocity is not constant. • Object projected horizontally will reach the ground at the same time as one dropped vertically.
Equations for Projectile Motion Horizontal Vertical ax=0 ay = - g vx= constant
Initial Velocity • If the ball returns to the y = 0 point, then the velocity at that point will equal the initial velocity. • At the highest point, v0 y = 0 and v = vx0
A football is kicked at an angle of 50.00 above the horizontal with a velocity of 18.0 m / s. Calculate the maximum height. Assume that the ball was kicked at ground level and lands at ground level. Example 3A at top:
Example 4A A football is kicked at an angle of 50.00 above the horizontal with a velocity of 18.0 m / s. The football hits a window in a house that is 25.0 m from where it was kicked. How high was the window above the ground. Time to hit the window:
What is the final velocity and angle of the football that hit the window in Example 4 A. Example 4 B below x axis
Example 5. (35) A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. If the plane is traveling horizontally with a speed of 250 km /h (69.4 m / s) how far in advance of the recipients (horizontal distance) must the goods be dropped (Fig. 3–37a)? . Coordinate system is 235 m below plane
Projectile Motion Is Parabolic In order to demonstrate that projectile motion is parabolic, the book derives y as a function of x. When we do, we find that it has the form: This is the equation for a parabola.