1 / 41

Lecture 31: MON 30 MAR Review Session : Midterm 3

Physics 2113 Jonathan Dowling. Lecture 31: MON 30 MAR Review Session : Midterm 3. EXAM 03: 8PM MON 30 MAR in Cox Auditorium. The exam will cover: Ch.26 through Ch.29 The exam will be based on: HW07 – HW10. The formula sheet for the exam can be found here:

zawacki
Download Presentation

Lecture 31: MON 30 MAR Review Session : Midterm 3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Physics 2113 Jonathan Dowling Lecture 31: MON 30 MAR Review Session : Midterm 3

  2. EXAM 03: 8PM MON 30 MAR in Cox Auditorium The exam will cover: Ch.26 through Ch.29 The exam will be based on: HW07 – HW10. The formula sheet for the exam can be found here: http://www.phys.lsu.edu/classes/fall2014/phys2113/downloads/FormulaSheetTest3.pdf You can see examples of old exam IIIs here: http://www.phys.lsu.edu/faculty/gonzalez/Teaching/Phys2102/Phys2102OldTests/

  3. V = i R E = Jρ Current and Resistance i = dq/dt R = ρL/A Junction rule r = ρ0(1+a(T-T0))

  4. Current and Resistance

  5. Current and Resistance: Checkpoints, Questions

  6. A cylindrical resistor of radius 5.0mm and length 2.0 cm is made of a material that has a resistivity of 3.5x10-5Ωm. What are the (a) current density and (b) the potential difference when the energy dissipation rate in the resistor is 1.0W?

  7. Circuits i = dq/dt Junction rule

  8. Multiloop Single loop DC Circuits Loop rule V = iR P = iV

  9. Resistors vs Capacitors ResistorsCapacitors Key formula: V=iR Q=CV In series: same current same charge Req=∑Rj 1/Ceq=∑1/Cj In parallel: same voltage same voltage 1/Req=∑1/Rj Ceq=∑Cj

  10. Resistorsin Series and in Parallel • What’s the equivalent resistance? • What’s the current in each resistor? • What’s the potential across each resistor? • What’s the current delivered by the battery? • What’s the power dissipated by each resisitor?

  11. Series and Parallel

  12. Series and Parallel

  13. Series and Parallel

  14. Circuits: Checkpoints, Questions

  15. Problem: 27.P.018. [406649] Figure 27-33 shows five 5.00 resistors. (Hint: For each pair of points, imagine that a battery is connected across the pair.) Fig. 27-33 (a) Find the equivalent resistance between points F and H. (b) Find the equivalent resistance between points F and G. Slide Rules: You may bend the wires but not break them. You may slide any circuit element along a wire so long as you don’t slide it past a three (or more) point junction or another circuit element.

  16. Problem: 27.P.046. [406629] In an RC series circuit, E = 17.0 V, R = 1.50 MΩ, and C = 1.80 µF. (a) Calculate the time constant. (b) Find the maximum charge that will appear on the capacitor during charging. (c) How long does it take for the charge to build up to 16.0 µC?

  17. v F L Magnetic Forces and Torques

  18. Side view Top view C C (28-13)

  19. (28-14)

  20. Ch 28: Checkpoints and Questions

  21. v F B into blackboard. Circular Motion: Since magnetic force is perpendicular to motion, the movement of charges is circular. r In general, path is a helix (component of v parallel to field is unchanged).

  22. . electron Radius of Circlcular Orbit . C r Angular Frequency: Independent of v Period of Orbit: Independent of v Orbital Frequency: Independent of v

  23. Problem: 28.P.024. [566302] In the figure below, a charged particle moves into a region of uniform magnetic field , goes through half a circle, and then exits that region. The particle is either a proton or an electron (you must decide which). It spends 160 ns in the region. (a) What is the magnitude of B? (b) If the particle is sent back through the magnetic field (along the same initial path) but with 3.00 times its previous kinetic energy, how much time does it spend in the field during this trip?

  24. Highest Torque: θ = ±90° sinθ = ±1 θ = 0° –cosθ = –1 θ = 180° –cosθ = +1 B Lowest Torque: θ= 0° & 180° sinθ = 0

  25. Right Hand Rule: Given Current i Find Magnetic Field B 

  26. Force on each wire due to currents in the other wires? Magnetic field? Checkpoints/Questions Ampere’s Law: Find Magnitude of ∫B∙ds?

  27. Right Hand Rule: Given Current i Find Magnetic Field B  The current in wires A,B,D is out of the page, current in C is into the page. Each wire produces a circular field line going through P, and the direction of the magnetic field for each is given by the right hand rule. So, the circles centers in A,B,D are counterclockwise, the circle centered at C is clockwise. When you draw the arrows at the point P, the fields from B and C are pointing in the same direction (up and left).

  28. Right Hand Rule & Biot-Savart: Given i Find B  • A length of wire is formed into a closed circuit with radii a and b, as shown in the Figure, and carries a current i. • (a) What are the magnitude and direction of B at point P? • (b) Find the magnetic dipole moment of the circuit. μ=NiA

More Related