Physics 101: Lecture 19 Elasticity and Oscillations

Physics 101: Lecture 19 Elasticity and Oscillations

Overview • Springs (review) • Restoring force proportional to displacement • F = – k x (Hooke’s law) • U = ½ k x2 • Today • Simple Harmonic Motion • Harmonic motion vs. circular motion 05

relaxed position FX = 0 x x=0 Springs • Hooke’s Law:The force exerted by a spring is proportional to the distance the spring is stretched or compressed from its relaxed position. • FX = – k xWhere xis the displacement from the relaxed position and k is the constant of proportionality. 18

Springs • Hooke’s Law:The force exerted by a spring is proportional to the distance the spring is stretched or compressed from its relaxed position. • FX = – k x Where xis the displacement from the relaxed position and k is the constant of proportionality. relaxed position FX = –kx > 0 x • x  0 x=0 18

Potential Energy in Spring • Force of spring is Conservative • F = – k x • W (by spring) = – 1/2 k x2 • Work done only depends on initial and final position • Define Potential Energy Uspring = ½ k x2 Force work x 20

FX = - kx < 0 • x > 0 Springs ACT • Hooke’s Law:The force exerted by a spring is proportional to the distance the spring is stretched or compressed from its relaxed position. • FX = – k xWhere xis the displacement from the relaxed position and k is the constant of proportionality. What is force of spring when it is stretched as shown below. A) F > 0 B) F = 0 C) F < 0 relaxed position x x=0 14

Simple Harmonic Motion • Vibrations • Vocal cords when singing/speaking • String/rubber band • Simple Harmonic Motion • Restoring force proportional to displacement • Springs F = –kx • Motion is a sine or cosine wave! 11

x +A CORRECT t -A Spring ACT II A mass on a spring oscillates up & down with simple harmonic motion of amplitude A. A plot of displacement (x) versus time (t) is shown below. At what points during its oscillation is the magnitude of the acceleration of the block biggest? 1. When x = +A or –A (i.e. maximum displacement) 2. When x = 0 (i.e. zero displacement) 3. The acceleration of the mass is constant F=ma 17

Simple Harmonic Motion: Anatomy X=0 X=A; v=0; a=-amax X=0; v=-vmax; a=0 X=-A; v=0; a=amax X=0; v=vmax; a=0 X=A; v=0; a=-amax X=-A X=A a = F/m = -kx/m 32

m x 0 PES x 0 Energy • A mass is attached to a spring and set to motion. The maximum displacement is x=A • SWnc = DK + DU • 0 = DK + DU  total energy is constant Energy = ½ k x2 + ½ m v2 • At maximum displacement x=A, v = 0 Energy = ½ k A2 + 0 • At zero displacement x = 0 Energy = 0 + ½ mvm2 Since Total Energy is same ½ k A2 = ½ m vm2 vm = (k/m) A -A A 25

x +A CORRECT t -A Preflight 1 A mass on a spring oscillates up & down with simple harmonic motion of amplitude A. A plot of displacement (x) versus time (t) is shown below. At what points during its oscillation is the speed of the block biggest? 1. When x = +A or -A (i.e. maximum displacement) 2. When x = 0 (i.e. zero displacement) 3. The speed of the mass is constant 30% 56% 14% 29

x +A CORRECT t -A Preflight 3 A mass on a spring oscillates up & down with simple harmonic motion of amplitude A. A plot of displacement (x) versus time (t) is shown below. At what points during its oscillation is the total energy (K+U) of the mass and spring a maximum? (Ignore gravity). 1. When x = +A or -A (i.e. maximum displacement) 2. When x = 0 (i.e. zero displacement) 3. The energy of the system is constant. 20% 13% 67% 27

SHM and Circles

x = R cos q =R cos (wt) sinceq = wt x 1 1 R 2 2 3 3  0 y 4 6 -R 4 6 5 5 What does moving in a circlehave to do with moving back & forth in a straight line ?? harmonic motion demo x 8 8 q R 7 7 34

Simple Harmonic Motion: x(t) = [A]cos(t) v(t) = -[A]sin(t) a(t) = -[A2]cos(t) x(t) = [A]sin(t) v(t) = [A]cos(t) a(t) = -[A2]sin(t) OR Period = T (seconds per cycle) Frequency = f = 1/T (cycles per second) Angular frequency =  = 2f = 2/T Natural freq. for spring:  = (k/m) xmax = A vmax = A amax = A2 Mass/spring demo 36

Example A 3 kg mass is attached to a spring (k=24 N/m). It is stretched +5 cm. At time t=0 it is released and oscillates. Which equation describes the position as a function of time x(t) = A) 5 sin(wt) B) 5 cos(wt) C) 24 sin(wt) D) 24 cos(wt) E) -24 cos(wt) We are told at t=0, x = +5 cm. x(t) = 5 cos(wt) only one that works. 39

Example A 3 kg mass is attached to a spring (k=24 N/m). It is stretched 5 cm. At time t=0 it is released and oscillates. What is the total energy of the block spring system? A) 0.03 J B) 0.05 J C) 0.08 J E = U + K At t=0, x = 5 cm and v=0: E = ½ k x2 + 0 = ½ (24 N/m) (5 cm)2 = 0.03 J 43

Example A 3 kg mass is attached to a spring (k=24 N/m). It is stretched 5 cm. At time t=0 it is released and oscillates. What is the maximum speed of the block? A) 0.45 m/s B) 0.23 m/s C) 0.14 m/s E = U + K When x = 0, maximum speed: E = ½ m v2 + 0 .03 J = ½ (3 kg) v2 v = 0.14 m/s 46

Example A 3 kg mass is attached to a spring (k=24 N/m). It is stretched 5 cm. At time t=0 it is released and oscillates. How long does it take for the block to return to x=+5cm? A) 1.4 s B) 2.2 s C) 3.5 s w = (k/m) = (24/3) = 2.83 radians/sec Returns to original position after 2 p radians T = 2 p / w = 6.28 / 2.83 = 2.2 seconds 49

Summary • Springs • F = -kx • U = ½ k x2 • w = (k/m) • Simple Harmonic Motion • Occurs when have linear restoring force F= -kx • x(t) = [A] cos(wt) or [A] sin(wt) • v(t) = -[Aw] sin(wt) or [Aw] cos(wt) • a(t) = -[Aw2] cos(wt) or -[Aw2] sin(wt) 50

Young’s Modulus • Spring F = -k x • What happens to “k” if cut spring in half? • A) decreases B) same C) increases • k is inversely proportional to length! • Define • Strain = DL / L المطاوعــة • Stress = F/A الضغط • Now • Stress = Y Strain • F/A = Y DL/L • k = Y A/L from F = k x Or F =kDL • Y (Young’s Modulus) independent of L 09

Physics 101: Lecture 19 Elasticity and Oscillations