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Chapter 13 Quadratic Relations and Functions

Corresponding Notes. Date Assigned. Assignment. #. Day 1 & 2. Solving Quadratic Equations. Friday 3/9. Page 507: 3 – 12 (all) 15 – 42 every 3 rd ( 1 st column). 1. Day 3 Notes Word Problems Consecutive ntegers. Monday 3/12. Worksheet: HW Day 3 Consecutive Integer. 2.

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Chapter 13 Quadratic Relations and Functions

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  1. Corresponding Notes Date Assigned Assignment # Day 1 & 2 Solving Quadratic Equations Friday 3/9 Page 507: 3 – 12 (all) 15 – 42 every 3rd ( 1st column) 1 Day 3 Notes Word Problems Consecutive ntegers Monday 3/12 Worksheet: HW Day 3 Consecutive Integer 2 Day 4 Notes Geometric Word Problems Tuesday 3/13 Worksheet: HW Day 4 Geometric word problems 3 Day 5 Notes More Word Problems Wednesday 3/14 Worksheet: HW Day 5 More Geometric word problem 4 Day 6 Notes Graphing Quadratics Thursday 3/15 Worksheet: Parabolas 5 Chapter 13 Quadratic Relations and Functions

  2. Warm up: Factor x2 – 10x + 21

  3. Let x= integer, x + 1 , x +2 Let x= even, x + 2 , x +4 Let x= odd, x + 2 , x +4

  4. EXAMPLES: • When the square of a certain number is diminished by 9 times the number the result is 36. Find the number. • 2. A certain number added to its square is 30. Find the number. x2 – 9x = 36 x2 – 9x – 36=0 (x – 12)(x + 3) = 0 x – 12 = 0 x + 3 = 0 x = 12 x = -3 x2 + x = 30 (x – 5)(x + 6) = 0 x2 + x – 30=0 x – 5 = 0 x + 6 = 0 x = 5 x = -6

  5. The square of a number exceeds the number by 72. Find the number • 4. Find two positive numbers whose ratio is 2:3 and whose product is 600. x2 + x = 72 x2 + x – 72 = 0 (x – 8)(x + 9) = 0 x – 8 = 0 x + 9 = 0 x = 8 x = -9 6(x2 – 100 ) = 0 GCF 6(x + 10)(x – 10)=0 D2PS (2x)(3x) =600 Let 1st = 2x 2nd = 3x 6x2 = 600 6x2 – 600 = 0 x – 10 = 0 x + 10 = 0 x = 10 x = -10

  6. The product of two consecutive odd integers is 99. Find the integers. • 6. Find two consecutive positive integers such that the square of the first is decreased by 17 equals 4 times the second. x(x + 2) = 99 (x – 9)(x + 11) = 0 Let 1st = x 2nd = x + 2 x2 + 2x = 99 x2 + 2x - 99 = 0 x – 9 = 0 x + 11 = 0 x = 9 x = -11 Solution: 9,11 or -9,-11 x2 - 17 = 4(x + 1) Let 1st = x 2nd = x + 1 x2 – 17 = 4x + 4 -4x -4x (x – 7)(x + 3) = 0 x2 – 4x - 17 = 4 x – 7 = 0 x + 3 = 0 -4 -4 x = 7 x = -3 x2 – 4x - 21 = 0

  7. The ages of three family children can be expressed as consecutive integers. The square of the age of the youngest child is 4 more than eight times the age of the oldest child. Find the ages of the three children. • 8. Find three consecutive odd integers such that the square of the first increased the product of the other two is 224. x2 = 8(x + 2) + 4 Let youngest = x 2nd = x + 1 oldest = x + 2 x2 + (x + 2)(x + 4)= 224 Let 1st = x 2nd = x + 2 3rd = x + 4

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