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AS 90285 . Mathematics 2.2 Draw straightforward non-linear graphs Level 2 3 Credits EXTERNAL. To Achieve you need to:. Given an equation be able to graph and identify key features of: Parabola Cubic and other polynomial functions Hyperbolae Circles Exponentials
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AS 90285 Mathematics 2.2 Draw straightforward non-linear graphs Level 2 3 Credits EXTERNAL
To Achieve you need to: Given an equation be able to graph and identify key features of: • Parabola • Cubic and other polynomial functions • Hyperbolae • Circles • Exponentials • Logarithmic functions
y 2 y = x 10 8 6 4 2 x -6 -4 -2 2 4 6 V e r t e x -2 Parabola • Basic form y=x2 • Vertexalways in the middlemirrors about this line
Vertical movements • When we add/subtract a number • For equations in the form: y= x2 + a
Identify the parabolas A A y = Vertex ( , ) B y = Vertex( , ) C y = Vertex ( , ) D y = Vertex ( , ) B C D
Horizontal movements • When we add/subtract a number inside the brackets • For equations in the form: y= (x + a)2
Identify the parabolas C A D B If we add a number inside the brackets it shifts left (negative direction) If we subtract a number inside the brackets it shifts right( + direction)
Factorised form • DO NOT expand • We can easily locate x-intercepts when in brackets • For equations in the form: y=(x+a)(x+b)
Steps to graph factorised form • Find x interceptstheses are when y=o • Find the vertexthis is always in the middle, so half way between the two x intercepts • Plot the vertex, x intercepts and join with a smooth curve following the pattern of the basic parabola
EXAMPLE: y=(x+3)(x-1) • x intercepts, set y=00=(x+3)(x-1)intercepts are at x=-3 and x=1 • VertexHalf way between x=-3 and x=1 is x=-1sub this into equation to find y valuey =(-1+3)(-1-1) =(2)(-2) =-4so the coordinate of vertex is (-1,4)
Plot Key Points: x-intercepts Vertex y-interceptwhen x=o
Now your turn... y=(x-4)(x+2) Find • x-intercepts • Coordinates of vertex • y-intercept EXTRA: y=x(x-6)
KEY POINTS: x-intercepts x=-2 and x=4 Vertex (1,-9) y-intercept (0,-8)
Changing steepness If there is a number in front of the x2 it will either make the graph steeper or flatter • For equations in the form: y= ax2
The blue line is y=x2 The other lines are y = ½x2 y = 2x2
Summary • If the number in front is BIGGER than 1e.g. 3x2 means “3 times the x value squared”makes the parabola steeper than the basic y=x2 • if the number in front is smaller than 1 e.g. ¼x2 means “one quarter of the x value squared” makes the parabola flatter than the basic y=x2
You need to know how to: • Graph parabolas of the form: • y=x2 + a • y=(x+a)2 • y=(x+a)(x+b) • y= ax2 • Identify the key features • x-intercepts • vertex • y-intercepts
The Cubic Equations with x3 as their highest power
y 10 5 x -4 -2 2 4 -5 -10 The basic cubic y=x3 We can plot this by filling in a table to work out values of the graph
Vertical movements • When we add/subtract a number • For equations in the form: y= x3 + a
Examples: y=x3 + 5 y=x3 -3
General rule: when we have a cubic in the form y=x3 + a The graph moves up or down by a units
Horizontal movements • When we add/subtract a number inside the brackets • For equations in the form: y= (x + a)3
Examples: y=(x-4)3 y=(x+2)3
General rule: when we have a cubic in the form y=(x+ a)3 The graph moves LEFT or RIGHT by a units
Cubics in factorised form • DO NOT expand • We can easily locate x-intercepts when in brackets y=(x+a)(x+b)(x+c) NOTE: one or more of the letters could be zero e.g. y=x(x+2)(x-3) y= (x+7) x2 y=x(x-4)2
How to plot a factorised cubic #1. Find x-interceptsFound where y=0 #2. Find y-interceptsFound when x=0 #3. Is it negative or positive look at the signs in front of the x’s
y =(x-1)(x+4)(x+3) y = -x2 (x-2) y = (x+6)(x+5)(x+2) y = (x+3)(x-1)2 y = (x-1)(2-x)(x-4) For each of these find: #1. x-intercepts #2. y-intercept #3. is the cubic “+” or “-”
y A y =(x-1)(x+4)(x+3) 5 x -10 -5 5 10 -5 -10 y Intercept ( 0 , -12 ) -15
B y = -x2 (x-2) y 4 2 x -4 -2 2 4 y Intercept ( 0 , 0 ) -2 -4
y C 10 y Intercept y = (x+6)(x+5)(x+2) ( 0 , 60) 5 x -10 -5 5 -5 -10
D y y = (x+3)(x-1)2 10 8 6 4 y Intercept ( 0 , 3 ) 2 x -10 -5 5 -2 -4
E y y = (x-1)(2-x)(x-4) 10 y Intercept 8 ( 0 , 8 ) 6 4 2 x -2 2 4 6 8 10 -2 -4
The Circle This type of graph is different because: Every x-value has 2 coordinates Every y-value has 2 coordinates
Example: this is the graph of a circle with a radius of 5 Each point on the circle is the same distance away from (0,0)
General formula of a circle For circles centered at (0,0) x2 + y2 = r2 With r being the radius of the circle
Example: x2 + y2 = 4 1st we need to know the radius We find this by finding √4 √4=2 Meaning the radius is 2 We can then mark 2 units away from the origin on each of the axis and join the points with a compass…
y 4 2 x -4 -2 2 4 -2 -4 EXAMPLE: y2 + x2 = 4
Steps: • Find the radius • Plot on the axis • Join to make circle Try and draw: • x2 + y2 = 36 • x2 + y2 = 49 • x2 + y2 = 25 • x2 + y2 = 9 • x2 + y2 = 1 Then try: Ex 19.2 pg 169 Questions 2-5
copy this into your notes Exponential Curves y=ax a is the base this number must always be greater than 0 a can NEVER be equal to zero (a≠0) x is called the exponent This is the variable that changes When x=0 the graph is at y=1 (because anything to the power of 0 equals 1)
Lets take a look at y=2x Copy and complete (substitute values into your calculator) What happens to y as x gets bigger?
What about for y=0.5x Copy and complete (substitute values into your calculator) What happens to y as x gets bigger?
copy this into your notes y y 1 x 1 x Summary for exponentials • Are always in the form: y=ax • The graph alwayscuts the y axis at y=1 Growth Curve If a is greater than 1 we get a growth curvea>1 Decay Curve If a is less than 1 (i.e. decimal or fraction) we get a decay curve0<a<1
Lets see what happens when we change the value of a… What happens as a increases? What always happens at x=1? Is the graph ever below the x-axis?