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Chapter 9 - Sections 1& 2 Suggested Reading: Pages 299 - 305

Stoichiometry. Chapter 9 - Sections 1& 2 Suggested Reading: Pages 299 - 305. Stoichiometry. The study of the quantitative, or measurable, relationships that exist in chemical formulas and chemical reactions. Interpreting Balanced Chemical Equations. 2 H 2 + O 2  2 H 2 O.

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Chapter 9 - Sections 1& 2 Suggested Reading: Pages 299 - 305

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  1. Stoichiometry Chapter 9 - Sections 1& 2Suggested Reading: Pages 299 - 305

  2. Stoichiometry The study of the quantitative, or measurable, relationships that exist in chemical formulas and chemical reactions.

  3. Interpreting Balanced Chemical Equations 2 H2 + O2 2 H2O • Based on the mole ratio

  4. Mole Ratio • indicated by coefficients in a balanced equation 2 H2 + O2 2 H2O • Molar ratio of H2 to H2O is 2:2 • (Simplify 1:1) • Molar ratio of O2 to H2O is 1:2

  5. In terms of moles 2 H2 + O2 2 H2O 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

  6. In terms of mass 2 H2 + O2 2 H2O 4 grams of hydrogen react with 32 grams of oxygen to produce 36 grams of water.

  7. Law of Conservation of Matter & Mass O2 H2O H2 2 g 1 mol 2 mol 2 mol 32 g 18 g 1 mol 1 mol 1 mol VERIFIED! 2 H2 + O2 2 H2O 2 moles H2 react with 1 mole of O2 to form 2 moles of H2O. + = 4 g 32 g 36 g

  8. In terms of molecules 2 H2 + O2 2 H2O 2 hydrogen molecules react with 1 oxygen molecule to produce 2 water molecules. • Notice that the number of molecules is NOT the same on each side of the arrow.

  9. In terms of atoms 2 H2 + O2 2 H2O 4 atoms of hydrogen react with 2 atoms of oxygen to produce 2 water molecules, which are 4 atoms of hydrogen and 2 atoms of oxygen.

  10. In terms of volumes @ STP 2 H2 + O2 2 H2O 44.8 L of hydrogen gas react with 22.4 L of oxygen gas to produce 44.8 L of water vapor. • Notice that the number of liters of gas is NOT the same on each side of the arrow.

  11. Practice Problem #1 Lead will react with hydrochloric acid to produce lead (II) chloride and hydrogen. How many moles of hydrochloric acid are needed to completely react with 0.36 moles of lead? Oh, no … where do I start?

  12. Write an equation and balance it. Lead will react with hydrochloric acid to produce lead chloride and hydrogen. Pb + HCl  PbCl2 + H2 2

  13. Determine Mole Ratio How many moles of hydrochloric acid are needed to completely react with 0.36 moles of lead? Pb + HCl  PbCl2 + H2 2 hydrochloric acid “given” lead “wanted” Coefficient = 1 Coefficient = 2

  14. Set up mole ratio “wanted” to “given” 0.36 moles Pb 2 HCl = .72 moles HCl 1 Pb How many moles of hydrochloric acid are needed to completely react with 0.36 moles oflead? Pb + HCl PbCl2 + H2 2

  15. Umm … It would require 0.72 moles of hydrochloric acid. Is that right? That’s Correct!

  16. Hem, hem – you have 9 more problems … ready, go.

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