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300 m

Para hallar la distancia entre dos puntos inaccesibles A y B, fijamos dos puntos C y D tales que CD = 300 m, y medimos los siguientes ángulos: ADB = 25° , BDC = 40° , ACD= 46° y ACB = 32°. A. B. En el triángulo ADC: A = 180° – 65° – 46° = 69°.

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300 m

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  1. Para hallar la distancia entre dos puntos inaccesibles A y B, fijamos dos puntos C y D tales que CD = 300 m, y medimos los siguientes ángulos: ADB = 25° , BDC = 40° , ACD= 46° y ACB = 32° A B En el triángulo ADC: A = 180° – 65° – 46° = 69° Aplicamos el teorema del seno al triángulo ADC para obtener AC. Aplicamos el teorema del seno al triángulo BCD para obtener BC. 320 250 400 460 D C 300 m En el triángulo BCD: B = 180° – 40° – 78° = 62°

  2. c b = a = A B 291,24 m 218,40 m 320 250 400 460 Aplicamos el teorema del coseno al triángulo ABC para obtener AB. D C 300 m La longitud AB es: 156,96 m

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