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9.8 Interval of convergence. From the 2011 AP Calc BC exam. Find the interval of convergence. From the 2011 AP Calc BC exam. Use the ratio test (use with Absolute value) lim x n+1 . n n →∞ n+1 x n Simplifies to x lim n/n+1 = x
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From the 2011 AP Calc BC exam Find the interval of convergence
From the 2011 AP Calc BC exam Use the ratio test (use with Absolute value) lim xn+1 . n n→∞ n+1 xn Simplifies to x lim n/n+1 = x lim x n n→∞ n→∞ n+1 by the ratio test -1<x<1 What about the end points?
From the 2011 AP Calc BC exam Try x =1 Try x = -1 (-1) n+1 1/n (-1) n+1 (-1)n/nAlternating series = -1/n Nth term→0 negative harmonic series Converges Diverges (also a p series with p=1) Interval is -1<x<1 Note: the radius of converges is 1
Problem 12 Find the Interval of convergence. Check for convergence on the end points
Problem 12 Find the Interval of convergence. Check for convergence on the end points This is a geometric series. It converges when │r │< 1 r = x/7 Interval of convergence is (-7,7)
Find the Interval of convergence. Check for convergence on the end points
Find the Interval of convergence. Check for convergence on the end points
Find the Interval of convergence. Check for convergence on the end points
Find the Interval of convergence. Check for convergence on the end points