1 / 9

Warm up 12/6 or 7

Warm up 12/6 or 7 Write the equation of a line that is parallel to y = -3x –5 and goes through the point (6,10). Write the equation of a line that is perpendicular to y = -3x –5 and goes through the point (6,10). 3) Using elimination, solve the following system.

mmichelle
Download Presentation

Warm up 12/6 or 7

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Warm up 12/6 or 7 Write the equation of a line that is parallel to y = -3x –5 and goes through the point (6,10). Write the equation of a line that is perpendicular to y = -3x –5 and goes through the point (6,10). 3) Using elimination, solve the following system. a) x + y = 4 -3x + y = -8 b) 3x – 4y = -15 5x + y = -2

  2. Answers to warm up • y = -3x + 28 • Y = 1/3x +8 • A) Subtract the two lines : x + y = 4 • -3x + y = -8 • 4x = 12 x = 3 Substitute: y = 1 • (3, 1) • b) (-1, 3)

  3. Solving Systems by Elimination cont. Objective: To find the solution to a system of equations by elimination (addition). Remember: The solution is the point where the lines intersect.

  4. We will need to change both equations. We will have the y value drop out. 1) 2x + 3y = 6 +5x – 4y = -8 4(2x + 3y) = 6(4) 8x + 12y = 24 3(5x – 4y) = -8(3) +15x -12y = -24 23 x = 0 x = 0 Now plug 0 in for x into any of the 4 equations. 2(0) + 3y = 6 3y = 6 Y = 2 The solution is (0, 2)

  5. You Try: • 2x + 3y = 14 3x – 2y = -5 • 5x + 2y = -8 2x – 5y = -9 (1, 4) (-2, 1)

  6. Solve Systems by EliminationThis time both equations will be multiplied but one must be multiplied by opposite sign to be canceled out. Example 2) 4x+ 2y = -8 5x + 7y = 8 Step 1 – Choose one variable to eliminate. Let’s start with x. One line will need to be multiplied by a negative number since all coefficients are positive. Let’s choose the first line. -5(4x+ 2y) = -8(-5) 4(5x + 7y = 8(4) -20x -10y = 40 20x + 28y = 32 18y = 72 y=4 Now substitute y back in to any of the four equations find x.

  7. Example 2 Continued : 4x+ 2y = -85x + 7y = 8 4x + 2(4) = -8 4x + 8 = -8 -8 -8 4x = -16 X = -4 The solution is (-4,4)

  8. YOU TRY!! 8x+ 2 y = 0 5x + 3y = -7 Answer: (1,-4)

  9. Summary: What is the solution of a system of linear equations? Homework:7.4B WS

More Related