1 / 5

Tips on cracking Aptitude Questions on Distance, Speed & Time

Tips on cracking Aptitude Questions on Distance, Speed & Time [ https://learningpundits.com/module-view/49-speed-and-distance/2-self-assessment-quiz-on-speed-and-distance/ ].<br><br> LearningPundits helps Job Seekers make great CVs [ https://learningpundits.com/module-view/1-cv-preparation-for-freshers/1-cv-writing-tips-for-freshers/ ] , master English Grammar and Vocabulary [ https://learningpundits.com/course/4-english-grammar/ ] , ace Aptitude Tests [ https://learningpundits.com/course/11-mathematical-aptitude/ ], speak fluently in a Group Discussion [ https://learningpundits.com/module-view/6-group-discussion-questions/1-tips-for-speaking-in-a-group-discussion/ ] and perform well in Interviews [ https://learningpundits.com/course/2-personal-interview/ ] We also conduct weekly online contests on Aptitude and English [ https://learningpundits.com/contest ]. We also allow Job Seekers to apply for Jobs [ https://learningpundits.com/applyForJobs ]

LearningPundits
Download Presentation

Tips on cracking Aptitude Questions on Distance, Speed & Time

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 3 TIPS on cracking Aptitude Questions on Distance, Speed and Time

  2. Tip #1: Use the formula Speed = Distance/ time while ensuring that units are same Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. Calculate the duration of the flight. Solution: Let the average duration of the flight be t hours. Distance = 600 km. Average Speed (km/ hr) = 600/ t Average Speed – 200 = 600 / (t + 0.5) (600/ t) – 200 = 600 / (t + 0.5) (600 – 200 t) (t + 0.5) = 600 t => 2t2 + t - 3 = 0 =>t = 1 hr Duration of the flight = 1.5 hrs Question: Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 km/hr. But he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 P.M.? Solution: According to the question, (D / 10) – (D / 15) = 2 =>D = 60 km. Time taken to reach A at 10 km/hr = 60 / 10 = 6 hours. (Starting time is 8 AM) Therefore, we need to find the speed to cover 60 km should be in 5 hours. Hence, speed = 60 / 5 =12 km/hr.

  3. Tip #2: If a person travels same distances with different speeds, then the average speed is not the arithmetic mean but the harmonic mean. If a person covers a distance d first at x km/hr and then covers the same distance d at y km/hr, then the average speed is: = Total distance travelled/ Total time taken = 2d/ (d/x + d/y) = 2d/ [(yd + xd)/xy] = 2dxy/[d(x+y)] = 2xy/ x+y (Harmonic mean of x and y) Question: A travels 25km at 50 km/hr and then 25km again with 70km/hr. What is A’s average speed during the whole journey? Solution: Average speed for the whole journey = (2x50x70) / (50+70)= 58.3km/hr

  4. Tip #3: If A runs x times faster than B, A’s speed is actually 1+x the speed of B. • Question: A runs 1⅔ times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? • Solution: • Speed of A, Sa = 5/3 x Sb • Let the distance of the course be ‘d’ meters • Time taken by A to cover distance ‘d’ = Time taken by B to cover distance ‘d-80’ • d/[5/3 x Sb] = (d-80)/Sb • 3d = 5d – 400 • 2d = 640 => d = 200m • Question: A runs 1⅔ times faster than B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? • Solution: • Speed of A, Sa = (1 + 5/3) x Sb = 8/3 x Sb • Let the distance of the course be ‘d’ meters • Time taken by A to cover distance ‘d’ = Time taken by B to cover distance ‘d-80’ • d/[8/3 x Sb] = (d-80)/Sb • 3d = 8d – 640 • 5d = 640 => d = 128m

  5. About Us LearningPundits helps Job Seekers make great CVs, master English Grammar and Vocabulary , ace Aptitude Tests , speak fluently in a Group Discussion and perform well in Interviews. We also conduct weekly online contests on Aptitude and English. Job Seekers can also apply for jobs on LearningPundits. You can read more about Tips on cracking Aptitude Questions on Distance, Speed & Time.

More Related