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Yesterday’s Homework

Yesterday’s Homework. Page 611 # 19 Page 612 # 20. Calculate the pH of solutions having the following ion concentrations at 298 o K. [H + ] = 1.0 x 10 -2 log [H + ] = -2 pH = 2. Calculate the pH of solutions having the following ion concentrations at 298 o K.

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Yesterday’s Homework

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  1. Yesterday’s Homework Page 611 # 19 Page 612 # 20

  2. Calculate the pH of solutions having the following ion concentrations at 298o K. [H+] = 1.0 x 10-2 log[H+] = -2 pH = 2

  3. Calculate the pH of solutions having the following ion concentrations at 298o K. [H+] = 3.0 x 10-6 log[H+] = 0.477 – 6 = -5.523 pH = 5.523

  4. Calculate the pH of solutions having the following ion concentrations at 298o K. [OH-] = 8.2 x 10-6 log[OH-] = 0.913 – 6 = -5.087 pOH = 5.087

  5. Calculate the pH of solutions having the following ion concentrations at 298o K. pOH = 5.087 pH + pOH = 14 pH = 14 – pOH = 14 – 5.087 = 8.913

  6. Calculate the pH of solutions having the following ion concentrations at 298o K. [OH-] = 1.0 x 10-6 log[OH-] = -6 pOH = 6 pH = 14 – 6 = 8

  7. Calculate the pH of solutions having the following ion concentrations at 298o K. [OH-] = 6.5 x 10-4 log[OH-] = 0.812 - 4 pOH = 3.188 pH = 14 – 3.188 = 10.812

  8. Calculate the pH of solutions having the following ion concentrations at 298o K. [H+] = 3.6 x 10-9 log[H+] = 0.556 - 9 pH = 8.444 pOH = 14 – 8.444 = 5.556

  9. Calculate the pH of solutions having the following ion concentrations at 298o K. [H+] = .025

  10. Calculate the pH of solutions having the following ion concentrations at 298o K. [H+] = 2.5 x 10-2 log[H+] = 0.397 – 2 pH = 1.603 pOH = 14 – 1.603 = 12.397

  11. Now let’s try it the other way around…

  12. Given the pH, calculate the [H+] and [OH-] for the following solution. pH = 7.40 -log [H+] = 7.40 log [H+] = -7.40 = .60 – 8 [H+] = 4.0 x 10-8

  13. Given the pH, calculate the [H+] and [OH-] for the following solution. pOH = 14 – 7.40 = 6.60 log [OH-] = -6.60 = .40 – 7 [OH-] = 2.5 x 10-7

  14. One last thing… If you have a solution of 1.0 M HCl, what is the [H+]?

  15. One last thing… HCl is a strong acid. That means it dissociates completely. If [HCl] = 1.0, then [H+] = 1.0

  16. One last thing… Same with strong bases. If [NaOH] = 1.0, then [OH-] = 1.0

  17. Homework Page 614 Problems 21 & 22

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