P.2 Term 1 Chapter 16A

Sep 23, 2014

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P.2 Term 1 Chapter 16A. P.2 Term 1 Chapter 16B. P.2 Term 1 Chapter 16C.

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P.2 Term 1 Chapter 16A

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P.2 Term 1 Chapter 16A
P.2 Term 1 Chapter 16B
P.2 Term 1 Chapter 16C

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Lecture 16a

Lecture 16a. Metal Carbonyl Compounds. Introduction. The first metal carbonyl compound described was Ni(CO) 4 (Ludwig Mond , ~1890), which was used to refine nickel metal ( Mond Process ) Ni(CO) 4 is very volatile ( b.p . = 40 o C) and also very toxic!

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Notes P.1-2

Notes P.1-2. January 22, 2014. Objectives. You will be able to: Define metallic, ionic, and covalent bonds and explain their characteristics State if two atoms will form a covalent or ionic bond Write ionic formula units . Overview of bonding.

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Lecture 16a

Lecture 16a. Metal carbonyl compounds. Introduction. The first metal carbonyl compound described was Ni(CO) 4 (Ludwig Mond , ~1890), which was used to refine nickel metal ( Mond Process )

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probleem P 1 is reduceerbaar tot P 2 als  afbeelding  :P 1  P 2 zo dat:

algoritme in O(|I| qr ) time voor I in P: doe eerst A  P /* geeft I' in SAT van size O(| | r ) doe dan A. alg. A O(| | q ). yes/no.  P (I)  SAT. A  P O(| | r ). I  P. probleem P 1 is reduceerbaar tot P 2 als  afbeelding  :P 1  P 2 zo dat:

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2.P.1, 3.P.1, 4.P.1, 5.P.1

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r 2 p 1

S 0 r0p0 S 0 S 0 r2p1 S 0 S 0 r1p0 S 1 S 1 r1p2 S 0 S 1 r0p1 S 1 S 1 r2p2 S 1. B. A. r 2 p 0. r 2 p 1. r 1 p 0. Figure 4. S 1. S 0. S 2. r 2 p 2. r 0 p 0. r 0 p 1. r 1 p 2. r 1 p 1. r 0 p 2. 0 1 2 Terminator AGTCTT GGTATT CTCGTT TGCTGA

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2) Long term (1/4)

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Alive-O 2 Term 1: Lesson 2

Alive-O 2 Term 1: Lesson 2. Together Again. Billy By Himself One morning Billy sat up in the bed. He said, ‘I am Billy. I am five. I can do things by myself.’. He climbed out of bed, ‘I can dress myself’, said Billy. And he did. He went to the bathroom. ‘I can wash myself’,

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P.4 Term 2 Chapter 2A

P.4 Term 2 Chapter 2A. P.4 Term 2 Chapter 2B. P.4 Term 2 Chapter 2C.

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 V 1 2 / 2 + p 1 /  + gz 1 =  V 2 2 /2 + p 2 /  + gz 2 + h lT

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Year 1 Autumn Term 2

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P 1 V 1 = P 2 V 2

Boyle’s Law. y = A / x. Pressure = A Volume. PV = constant. P 1 V 1 = P 2 V 2. ↑ P ↓ V. Inverse relationship. ↓P ↑V. Practice Problem A gas occupies a volume of 3.86 L at 0.750 atm . At what pressure will the volume be 4.86 L ?. V 1. P 1. ? P 2. V 2.

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Sections P.1 – P.2 Review

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p 2 1 /a

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p 1 = 1/6, p 2 = 1/3, n = 5

p 1 = 1/6, p 2 = 1/3, n = 5.

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