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Learn about momentum in collisions and explosions, elastic versus inelastic collisions, impulse, and momentum theorem. Dive into examples of completely inelastic collisions and explosions solving for final velocities and directions. Understand the concept of the center of mass in systems.
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Lecture 12:Collisions and Explosions • Momentum Examples! • Problem Solving • Collisions (elastic & inelastic) • Explosions
Impulse and Momentum:quick review • Momentum-Impulse Theorem • FtI = pf- pi=p • For single object…. • If F = 0, then momentum conserved (p = 0) • For “system” of objects … • ptotal p • Internal forces: forces between objects in system • External forces: all other forces • Fextt=ptotal • if Fext = 0 , then total momentum conserved (ptotal = 0) • Applications: Collisions & Explosions
“before” m2 m1 “after” m2 m1 “before” M “after” m2 m1 Collisions Procedure • Draw “before”, “after” • Define system so that Fext = 0 • Set up axes • Compute Ptotal “before” • Compute Ptotal “after” • Set them equal to each other Explosions
Some Terminology • Elastic Collisions: collisions that conserve mechanical energy • Inelastic Collisions: collisions that do not conserve mechanical energy • Completely Inelastic Collisions: objects stick together
y x Collision Example • Two cars are approaching an intersection. The first car is 1520 kg and is moving east at 18 m/s; the second car is 1380 kg and is moving north at 16 m/s. The cars have a completely inelastic collision. What is their final velocity? Before: After:
y x Collision Example • Two cars are approaching an intersection. The first car is 1520 kg and is moving east at 18 m/s; the second car is 1380 kg and is moving north at 16 m/s. The cars have a completely inelastic collision. What is their final velocity? x-direction: pix = pfx (1520 kg)(18 m/s) + 0 = pfx y-direction: piy = pfy 0 + (1380 kg)(16 m/s) = pfy
y x Collision Example • Two cars are approaching an intersection. The first car is 1520 kg and is moving east at 18 m/s; the second car is 1380 kg and is moving north at 16 m/s. The cars have a completely inelastic collision. What is their final velocity? x-direction: (1520 kg)(18 m/s) + 0 = pfx (1520 kg)(18 m/s) = (1520 kg + 1380 kg) vfx y-direction: 0 + (1380 kg)(16 m/s) = pfy (1380 kg)(18 m/s) = (1520 kg + 1380 kg) vfy
y x Collision Example • Two cars are approaching an intersection. The first car is 1520 kg and is moving east at 18 m/s; the second car is 1380 kg and is moving north at 16 m/s. The cars have a completely inelastic collision. What is their final velocity? x-direction: vfx = 9.43 m/s y-direction: vfy = 7.61 m/s Vf = 12.1 m/s at 51º east of north
y x Explosion Example • A ball has a mass of 3 kg. It explodes into three equal masses, shooting a 1 kg piece in the positive y direction with speed v and another 1 kg piece in the positive x direction with speed v. What is the speed and direction of the remaining 1 kg piece? Before: After:
y x Explosion Example • A ball has a mass of 3 kg. It explodes into three equal masses, shooting a 1 kg piece in the positive y direction with speed v and another 1 kg piece in the positive x direction with speed v. What is the speed and direction of the remaining 1 kg piece? x-direction: pix = pfx 0 + 0 + 0 = 0 + (1 kg) v + (1 kg) vfx y-direction: piy = pfy 0 + 0 + 0 = (1 kg) v + 0 + (1 kg) vfy
y x Explosion Example • A ball has a mass of 3 kg. It explodes into three equal masses, shooting a 1 kg piece in the positive y direction with speed v and another 1 kg piece in the positive x direction with speed v. What is the speed and direction of the remaining 1 kg piece? x-direction: vfx = -v y-direction: vfy = -v Vf = v 2 at 45º below the –x axis
Center of Mass = Balance point L m m L m 5m Center of Mass Example 1: xCM = (0 + mL)/2m = L/2 Example 2: xCM = (0 + 5mL)/6m = 5L/6 X=0 X=L
Summary • Collisions and Explosions • Draw “before”, “after” • Define system so that Fext = 0 • Set up axes • Compute ptotal “before” • Compute ptotal “after” • Set them equal to each other • Center of Mass (Balance Point)