1 / 22

Gay-Lussac’s Law of Combining Volumes of Gases

Gay-Lussac’s Law of Combining Volumes of Gases. “Under the same conditions of temperature and pressure, the volumes of reacting gases and of their gaseous products are expressed in ratios of small whole numbers.”. Avogadro’s Principle.

adria-ewing
Download Presentation

Gay-Lussac’s Law of Combining Volumes of Gases

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Gay-Lussac’s Law of Combining Volumes of Gases

  2. “Under the same conditions of temperature and pressure, the volumes of reacting gases and of their gaseous products are expressed in ratios of small whole numbers.”

  3. Avogadro’s Principle

  4. “Equal volumes of all gases, under the same conditions of temperature and pressure, contain the same number of molecules.”

  5. Molar Volume “The volume occupied by one mole of a gas at standard temperature and pressure (STP).”

  6. Based on Avogadro’s principle, the molar volume of any gas at STP is 22.4 Liters

  7. The volume of any gas is directly proportional to the number of moles (n) of the gas, if pressure and temperature are constant.

  8. V a n (p and T constant)

  9. The volume of a gas is inversely proportional to the pressure applied to it if the quantity of gas (n) and temperature are constant.

  10. (n and P constant)

  11. The volume of gas is directly proportional to the Kelvin temperature if the pressure and quantity of gas remain constant.

  12. V a T p and n constant

  13. Therefore: V a n x 1/p x T

  14. By inserting a proportionality constant R of suitable dimensions, this proportion can be stated as an equation.

  15. pV = nRT

  16. Solving for R:

  17. Using the appropriate units the equation is stated:

  18. R = 0.082057 L atm/mole K

  19. 42 g of oxygen is heated to 100o C. If the pressure is 1.45 atm, what is the volume?

  20. P = 1.30 atm V = ? m = 42 g n = 42g/32g/mol n = 1.31 R = .082057 T = 100 o C = 373 K

  21. What is the mass of 41 L of chlorine at 28o C and 788 mm of Hg? p = 788 mm Hg V = 41 L n = ? m = (n)(g/mol) R = .082057 T = 28oC = 301 K

More Related