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Recombination Frequency and Gene Linkage Mapping. Linked vs. Unlinked Genes. Crossing Over. Crossover Frequency. Mapping Using Frequency. Mapping Gene Loci. Recombination frequency. (Recombinant offspring) (Total offspring).
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Recombination frequency (Recombinant offspring) (Total offspring)
A wild-type fruit fly (heterozygous for gray body color and normal wings) was mated with a black fly with vestigial wings. The offspring has the following phenotypic distribution: Wild type (gray-normal) 778 Black-vestigial 785 Black-normal 158 Gray-vestigial 162 What is the recombination frequency between these genes for body color and wing type?
A wild-type fruit fly (heterozygous for gray body color and normal wings) was mated with a black fly with vestigial wings. The offspring has the following phenotypic distribution: • Wild type 778 • Black-vestigial 785 • Black normal 158 • Gray vestigial 162 • What is the recombination frequency between these genes for body color and wing type? (158+162) / (778+785+158+162) 320/1873 0.171 = 17.1%
In rabbits the dominant allele B produces a black coat color and the recessive genotype bb produces a brown coat. • Body fat color in rabbits is white if a dominant allele Y is present and yellow if the genotype is yy. • Assume the mating between rabbits with the following genotypes :Black with white fat – BBYYBrown with yellow fat - bbyy • produces the dihybrid - BbYy Black with white fat • Calculate the recombination frequency if the dihybrids are mated back to brown rabbits having yellow fat, bbyy, and the following ratio of phenotypes is observed: • BlackWhite125 • BlackYellow75 • BrownWhite85 • BrownYellow115
In rabbits the dominant allele B produces a black coat color and the recessive genotype bb produces a brown coat. Body fat color in rabbits is white if a dominant allele Y is present and yellow if the genotype is yy. Assume the mating between rabbits with the following genotypes :Black with white fat - BBYYBrown with yellow fat - bbyy produces the dihybrid - BbYy Calculate the recombination frequency if the dihybrids are mated back to brown rabbits having yellow fat, bbyy, and the following ratio of phenotypes is observed: BlackWhite125 BlackYellow75 BrownWhite85 BrownYellow115 (75+85) / (125+115+75+85) 160/400 0.40 = 40%
Question #1 • In rabbits, black (B) is dominant to brown (b), while full color (F) is dominant to chinchilla (f). The genes controlling these traits are linked. • The following cross was made: rabbits heterozygous for both traits that express black, full color, (BbFf) with rabbits that are brown, chinchilla (bbff). The following results were obtained: • 31 brown, chinchilla (bbff) • 35 black, full (B-F-) • 16 brown, full • 19 black, chinchilla • Determine the map distance between the 2 genes.
Question #1 In rabbits, black (B) is dominant to brown (b), while full color (F) is dominant to chinchilla (f). The genes controlling these traits are linked. The following cross was made: rabbits heterozygous for both traits that express black, full color, with rabbits that are brown, chinchilla. The following results were obtained: 31 brown, chinchilla 35 black, full 16 brown, full 19 black, chinchilla Determine the map distance between the 2 genes (16+19) / (31+35+16+19) 35/101 0.35 = 35% 35 map units
Determine the sequence of genes along a chromosome based on the following recombination frequencies: • b – vg 17 • cn-vg 8 • b-cn 9
Determine the sequence of genes along a chromosome based on the following recombination frequencies: b – vg 17 cn-vg 8 b-cn 9
Determine the sequence of genes along a chromosome based on the following recombination frequencies: b – vg 17 cn-vg 8 b-cn 9
Determine the sequence of genes along a chromosome based on the following recombination frequencies: • A-B 8 • A-C 28 • A-D 25 • B-C 20 • B-D 33
Determine the sequence of genes along a chromosome based on the following recombination frequencies: A-B 8 A-C 28 A-D 25 B-C 20 B-D 33