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Empirical formulas and percentage yields

Solve chemical equations, derive empirical formulas, and calculate percentage yields in this chemistry practice session. Topic includes the Contact Process, SO3 production, and more.

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Empirical formulas and percentage yields

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  1. Sunday, 05 November 2017 Empirical formulas and percentage yields Starter The Contact Process is used to manufacture sulfuric acid. Sulfur trioxide is needed to be made in an intermediate step. SO2 + O2 SO3 Balance the equation How much SO3 can be made from 96g of SO2?

  2. Empirical formula An empirical formula is the smallest ratio of the atoms in a compound For example: C4H10 Both numbers can divide by 2 so the empirical formula is C2H5 What about C2H4O2?

  3. Practice Work out the empirical formula for: H2O2 Pb2O4 C3H6 Al2Cl6 C6H12O6 Extension: How can we use empirical formula and relative formula mass to prove that an equation is fully balanced: C + O2 CO2

  4. Percentage yield Either: (Number of actual moles/Expected moles) x 100 (Actual mass/theoretical mass) x 100 50g of calcium carbonate reacts with hydrochloric acid to produce calcium chloride, water and carbon dioxide. What if only 44g of calcium chloride was made, what would the percentage yield be?

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