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Empirical Formulas

Empirical Formulas. Grab A CALCULATOR AND GET OUT A PIECE OF PAPER FOR NOTES. Empirical Formula. An empirical formula is a formula that shows the smallest whole number ratio of the elements in a compound. Empirical Formula. Review 

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Empirical Formulas

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  1. Empirical Formulas Grab A CALCULATOR AND GET OUT A PIECE OF PAPER FOR NOTES.

  2. Empirical Formula An empirical formula is a formula that shows the smallest whole number ratio of the elements in a compound.

  3. Empirical Formula • Review  • Percent composition shows the percentage of the compound made up of each element Mass of Element _______________ X 100 Mass of Compound • CO2 Fe2O3 • We use the percent composition to calculate the empirical formula

  4. Empirical Formula • Example – • Methyl acetate is made up of 48.64% carbon, 8.16 % hydrogen, and 43.20% oxygen. Find the empirical formula methyl acetate. • Step 1  find the moles of each element assuming you have a total mass of 100 g Carbon  48.64 g C 1 mol C = 4.050 mol C 12.01 g C Hydrogen  8.16 g H 1 mol H = 8.10 mol H 1.008 g H Oxygen  43.20 g O 1 mol O = 2.700 mol O 15.999 g O

  5. Empirical Formula • Example – • Methyl acetate is made up of 48.64% carbon, 8.16 % hydrogen, and 43.20% oxygen. Find the empirical formula methyl acetate. • Step 2  Divide all moles by the smallest number Carbon  4.050 mol C = 1.500 mol 2.70 mol Hydrogen  8.10 mol H = 3.00 mol 2.70 mol Oxygen  2.700 mol O = 1.00 mol 2.70 mol

  6. Empirical Formula • Example – • Methyl acetate is made up of 48.64% carbon, 8.16 % hydrogen, and 43.20% oxygen. Find the empirical formula methyl acetate. • Step 3  Multiply each by the same number to get a whole number Carbon  1.500 mol x 2 = 3 Hydrogen  3.00 mol x 2 = 6 Oxygen  1.00 mol x 2 = 2 So, the empirical formula is C3H6O2

  7. http://youtu.be/AFqwtY7m2PI Calculate the percent composition of Calcium Chloride assuming you have a 100 g sample. Determine the emperical formula for a compound with 60.98% arsenic and 39.02% sulfur. Determine the emperical formula for a compound that contains 74.03% C, 8.70% H, and 17.27 % N.

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